CODEWITHSUNDEEP
javaregexregex-negationregex-lookarounds
Dranym
Dranym

Reputation: 13

Regex Negate Pattern

I'm having trouble getting the other side of this regex.

Stranger Number is %19. Friend Number is %30.

My current regex is this (%[0-9]+) So when I run this regex. The only highlighted are the %30 and %19.

Strange Number is %19. Friend Number is %30.

I just want it the other way around where %19 and %30 is not the highlighted one and everything else is highlighted.

I have tried. this one [^%](?![0-9]) but im not getting my expected output.

thanks for the help!

Upvotes: 1

Views: 81

Answers (2)

markspace
markspace

Reputation: 11020

For completeness, and those on earlier versions of Java, you can just use the Matcher and a while loop to extract strings that match a pattern.

   public static void main( String[] args ) {
      String test = "Number %1.  And number %2 also.";
      Matcher matcher = Pattern.compile( "%[\\d]+" ).matcher( test );
      ArrayList<String> results = new ArrayList<>();
      while( matcher.find() )
         results.add( matcher.group() );
      System.out.println( results );
   }

Upvotes: 1

Socowi
Socowi

Reputation: 27205

Depending you what you want to do, you don't have to find an inverted regex for (%[0-9]+).

For instance, if you planned to extract all substrings matching the inverted regex, you could use yourString.split("%[0-9]+").

If you planned to extract all the %... by splitting the string with yourString.split(invertedRegex) you could use a matcher instead.
Code taken from this answer.

String[] matches = Pattern.compile("%[0-9]+").matcher(yourString)
                          .results().map(MatchResult::group)
                          .toArray(String[]::new);

Upvotes: 1

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