Reputation: 63
I take a data string = "AkhilRanjanBiharabcdefghijklmnopMovedtoChennai18", encrypt it first and then decrypt it. The string which I get back on decryption is "AkhilRanjanBiharÙ†+™¸„À–ýæó@Movedtoñhennai18" which is almost fine for the first 16 and final 16 characters, but the 16 characters in the middle are absolute junk. What can possibly be going wrong?
My encryption code:-
public String encrypt(String value) {
log.info("This method is not going to be used");
String key = "theabcd@heymaths";
initVector = "{{{{{{{{{{{{{{{{";
String encryptedStr="";
byte[] encrBytes =null;
try {
IvParameterSpec iv = new IvParameterSpec(initVector.getBytes());
SecretKeySpec skeySpec = new SecretKeySpec(key.getBytes(), "AES");
Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding");
cipher.init(Cipher.ENCRYPT_MODE, skeySpec, iv);
encrBytes = cipher.doFinal(value.getBytes());
encryptedStr = new String(encrBytes);
} catch (Exception ex) {
ex.printStackTrace();
}
String strToBeEncoded = encryptedStr +"::"+initVector;
encrBytes = strToBeEncoded.getBytes();
//String encoded = Base64.encodeBase64String(encrBytes);
String encoded = Base64.getEncoder().encodeToString(encrBytes);
String urlEncoded = null;
try {
urlEncoded = java.net.URLEncoder.encode(encoded, CHARSET);
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return urlEncoded;
}
Decryption code:-
public String decrypt(String encrypted) {
String decryptedStr = null;
byte[] base64Bytes = null;
String urlDecoded = null;
String key = HmCommonProperty.getProperty("abcd_crypt_key");
if(key == null || key.isEmpty()) {
key = securityKey;
}
String encryptionMech = HmCommonProperty.getProperty("abcd_crypt_algo");
if(encryptionMech == null || encryptionMech.isEmpty()) {
encryptionMech = CRYPT_MECHANISM;
}
try {
//Url and Base64 decoding
urlDecoded = java.net.URLDecoder.decode(encrypted, CHARSET);
//base64Bytes = Base64.decodeBase64(urlDecoded);
base64Bytes = Base64.getDecoder().decode(urlDecoded);
//Generating IV
String str = new String(base64Bytes);
String[] bodyIVArr = str.split("::");
initVector = bodyIVArr[1];
String bodyStr = bodyIVArr[0];
//AES Decryption
Cipher cipher = Cipher.getInstance(encryptionMech);
IvParameterSpec iv = new IvParameterSpec(initVector.getBytes());
System.out.println("initVector Length -> "
+iv.getIV().length);
System.out.println("input length -> "
+bodyStr.getBytes().length);
SecretKeySpec skeySpec = new SecretKeySpec(key.getBytes(), "AES");
cipher.init(Cipher.DECRYPT_MODE, skeySpec, iv);
byte[] decryptedBytes = cipher.doFinal(bodyStr.getBytes());
decryptedStr = new String(decryptedBytes);
} catch (Exception ex) {
ex.printStackTrace();
log.error("Error occurred while decryption abcd data",ex);
}
return decryptedStr;
}
Upvotes: 1
Views: 1553
Reputation: 49629
Your encrypted data is a sequence of bytes. If you need to encode it as a string, you should use base64 or a similar encoding that is intended for encoding arbitrary byte arrays. Pretending that your arbitrary byte array is a valid string-encoding is going to cause you trouble, even if you use ISO_8859_1
.
Replace
encryptedStr = new String(encrBytes)
with
encryptedStr = Base64.getEncoder().encodeToString(encrBytes)
and replace
bodyStr.getBytes()
with
Base64.getDecoder().decode(bodyStr)
See also: How to correctly and consistely get bytes from a string for AES encryption?
Upvotes: 2
Reputation: 9543
Your error lies here:
encryptedStr = new String(encrBytes);
strToBeEncoded.getBytes();
These methods use the platform default character set, and when you convert from byte[]
to String
and back to byte[]
the process is lossy in the general case. The only way it's not lossy is if the platform default character set is "ISO_8859_1"
.
I changed all of 11 such calls to:
encryptedStr = new String(encrBytes, StandardCharsets.ISO_8859_1);
strToBeEncoded.getBytes(StandardCharsets.ISO_8859_1);
(I didn't change CHARSET
). The output I get now is:
initVector Length -> 16
input length -> 48
AkhilRanjanBiharabcdefghijklmnopMovedtoChennai18
Bonus warning 1: The encryption uses hardcoded "AES/CBC/NoPadding"
but the decryption is dynamic (it should of course also use "AES/CBC/NoPadding"
).
Bonus warning 2: The chance is low but it's entirely possible that "::"
appears inside the encrBytes
, screwing up your str.split("::");
. One solution is to search for the last occurrence of "::"
and only split on that.
Upvotes: 0