CODEWITHSUNDEEP
c++qtqt5selectionqtablewidget
froz
froz

Reputation: 163

Connecting selection of row in 2 QTableWidget

I am trying to connect row selections from two QTableWidget. I mean, when I select one row in Table 1, I want my program selects the same row in table 2. The two table dont have the same number of column so I cannot just select one item for the first and select the same item on the second able. I have tried to use the following without success:

connect(ui->table1->selectionModel(), SIGNAL(currentRowChanged(QModelIndex, QModelIndex)), ui->table2->selectionModel(), SLOT(setCurrentIndex(QModelIndex)));

It is written:

QObject::connect: No such slot QItemSelectionModel::setCurrentIndex(QModelIndex)

Do you know what is going wrong?

Upvotes: 1

Views: 957

Answers (1)

eyllanesc
eyllanesc

Reputation: 244132

The problem is caused because setCurrentIndex() has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow():

#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>

int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    auto *table1 = new QTableWidget(4, 3);
    table1->setSelectionBehavior(QAbstractItemView::SelectRows);
    auto table2 = new QTableWidget(4, 4);
    table2->setSelectionBehavior(QAbstractItemView::SelectRows);

    QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
                     [table2](const QModelIndex &current, const QModelIndex & previous)
    {
        if(previous.isValid())
            table2->selectRow(current.row());
    });

    QWidget w;
    auto lay = new QHBoxLayout(&w);
    lay->addWidget(table1);
    lay->addWidget(table2);
    w.show();

    return a.exec();
}

Upvotes: 1

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