CODEWITHSUNDEEP
bash
vamsi
vamsi

Reputation: 11

condition's statement gets skipped

i am new to scripting.how do i correct this bash script. for all values it gives me the "else" condition - "wrong value" 

     #!/bin/bash
     read -p "First Name: " $first
     read -p "Last Name: " $last
     read -p "profession 1 for software and 2 for hardware (1/2): " $pro
     echo $first
     if [ "$pro" == "1" ];then
        echo $first
        echo $last
     elif [ "$pro" == "2" ];then
     echo $first
     echo $last
     echo $pro
     else
        echo "wrong value!"
    fi

Upvotes: 0

Views: 32

Answers (1)

Red Cricket
Red Cricket

Reputation: 10460

You need to change …

read -p "First Name: " $first
read -p "Last Name: " $last
read -p "profession 1 for software and 2 for hardware (1/2): " $pro

… to …

read -p "First Name: " first
read -p "Last Name: " last
read -p "profession 1 for software and 2 for hardware (1/2): " pro

Note the lack of $ on first, last and pro. In shell you do not use the $ on a variable when assigning it a value.

Upvotes: 1

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