CODEWITHSUNDEEP
regexstringlistpython-3.6
Feyzi Bagirov
Feyzi Bagirov

Reputation: 1372

Splitting a string in Python based on a regex pattern

I have a bytes object that contains urls: 

> body.decode("utf-8") 
> 'https://www.wired.com/story/car-news-roundup-tesla-model-3-sales/\r\n\r\nhttps://cleantechnica.com/2018/11/11/can-you-still-get-the-7500-tax-credit-on-a-tesla-model-3-maybe-its-complicated/\r\n'

I need to split it into a list with each url as a separate element: 

import re
pattern = '^(http:\/\/www\.|https:\/\/www\.|http:\/\/|https:\/\/)?[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?$'

urls = re.compile(pattern).split(body.decode("utf-8"))

What I get is a list of one element with all urls pasted together: 

['https://www.wired.com/story/car-news-roundup-tesla-model-3-sales/\r\n\r\nhttps://cleantechnica.com/2018/11/11/can-you-still-get-the-7500-tax-credit-on-a-tesla-model-3-maybe-its-complicated/\r\n']

How do I split each url into a separate element?

Upvotes: 0

Views: 28

Answers (1)

Pushpesh Kumar Rajwanshi
Pushpesh Kumar Rajwanshi

Reputation: 18357

Try splitting it with \s+

Try this sample python code,

import re
s = 'https://www.wired.com/story/car-news-roundup-tesla-model-3-sales/\r\n\r\nhttps://cleantechnica.com/2018/11/11/can-you-still-get-the-7500-tax-credit-on-a-tesla-model-3-maybe-its-complicated/\r\n'
urls = re.compile('\s+').split(s)
print(urls)

This outputs,

['https://www.wired.com/story/car-news-roundup-tesla-model-3-sales/', 'https://cleantechnica.com/2018/11/11/can-you-still-get-the-7500-tax-credit-on-a-tesla-model-3-maybe-its-complicated/', '']

Does this result looks ok? Or we can work on it and make as you desire.

In case you don't want empty string ('') in your result list (because of \r\n in the end), you can use find all to find all the URLs in your string. Sample python code for same is following,

import re
s = 'https://www.wired.com/story/car-news-roundup-tesla-model-3-sales/\r\n\r\nhttps://cleantechnica.com/2018/11/11/can-you-still-get-the-7500-tax-credit-on-a-tesla-model-3-maybe-its-complicated/\r\n'
urls = re.findall('http.*?(?=\s+)', s)
print(urls)

This gives following output,

['https://www.wired.com/story/car-news-roundup-tesla-model-3-sales/', 'https://cleantechnica.com/2018/11/11/can-you-still-get-the-7500-tax-credit-on-a-tesla-model-3-maybe-its-complicated/']

Upvotes: 1

Related Questions