CODEWITHSUNDEEP
c++structdoublecomplex-numbers
Henryk5161
Henryk5161

Reputation: 19

Converting a defined structure into double (complex numbers) in c++

Im trying to find my way around defining structures, and coded this to define a complex number. Ive already had success working with them, adding multiplying e.g., but I dont know how to get the absolute value of my complex number converted into a double, my compiler keeps telling me it doesnt know how to convert it, even though the complex struct is literally made of 2 doubles.. 

    #include <iostream>
#include <cstdlib>
#include <cmath>

using namespace std;

struct Complex_Number { 
    double re, im;      
};
void print(const Complex_Number& w) //my print function for complex numbers
{
    cout  << '(' << w.re << " + i*" << w.im << ')';
}

 double abs(const Complex_Number& z )
{

   z = z.re + z.im;
  abs = sqrt((z.re*z.re)+(z.im*z.im)); 

   return abs;
   }




  int main()
{

 return 0;




}

Upvotes: 0

Views: 751

Answers (1)

Stephan Lechner
Stephan Lechner

Reputation: 35154

I don't know what you intend with z = z.re + z.im; The second part just needs to be assigned to a variable or returned directly. So write...

double abs(const Complex_Number& z ) {

  double ret = sqrt((z.re*z.re)+(z.im*z.im)); 

  return ret;
}

or

double abs(const Complex_Number& z ) {

  return sqrt((z.re*z.re)+(z.im*z.im)); 
}

Assigning something to the "function name" as in your code, i.e. abs = sqrt((z.re*z.re)+(z.im*z.im)), is not valid C++ code.

Upvotes: 1

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