CODEWITHSUNDEEP
pythonpython-3.xpython-2.7
V Anon
V Anon

Reputation: 543

rearranging order of elements within list

I am trying to rearrange the order of elements in a list.

I want to move the element at i + 1 position to the end of the list,

for len(list) - 2 times.

For example if I have

>>> 5 6 7 8 9 10 11 12 13 14 15

5 7 8 9 10 11 12 13 14 15 6

5 7 9 10 11 12 13 14 15 6 8

5 7 9 11 12 13 14 15 6 8 10

5 7 9 11 13 14 15 6 8 10 12

5 7 9 11 13 15 6 8 10 12 14

5 7 9 11 13 15 8 10 12 14 6

5 7 9 11 13 15 8 12 14 6 10

5 7 9 11 13 15 8 12 6 10 14

5 7 9 11 13 15 8 12 6 14 10 # desired output

Below is my code, but I just cannot figure out a way to remove the i + 1th element from the list and append it at the end of the list.

The code returns an error saying that pop index out of range and its quite frustrating.

def rearrange(sequence):
    test_list = list(sequence)

    length = len(test_list)
    for i in range(length - 2):
        stray_element = test_list.pop(i + 1)
        test_list.append(stray_element)

Upvotes: 1

Views: 168

Answers (1)

Rob Bricheno
Rob Bricheno

Reputation: 4653

The code you posted (after editing it to make it return, and providing an input sequence) works fine for me and produces the desired output.

my_sequence = [5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

def rearrange(sequence):
    test_list = list(sequence)

    length = len(test_list)
    for i in range(length - 2):
        stray_element = test_list.pop(i + 1)
        test_list.append(stray_element)
    return test_list

print(rearrange(my_sequence))

outputs:

[5, 7, 9, 11, 13, 15, 8, 12, 6, 14, 10]

(posted as an answer rather than a comment mainly because of formatting...)

Upvotes: 2

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