CODEWITHSUNDEEP
python
Codec
Codec

Reputation: 33

Python: Word guessing game

I'm trying to make a word guessing game in Python, but the final part is a bit confusing to me.

Here is my code uptil now:

word_tuple = ("c", "o", "d", "e", "c")

word = ""

word = input("Give a word of " +  str(len(word_tuple)) + " characters: ")

while len(word) != len(word_tuple):
    if len(word) != len(word_tuple):
        print("Wrong!")
        word = input("Give a word of " + str(len(word_tuple)) + " characters: ")

for i in range(len(word_tuple)):
    print(word_tuple[i], end="")

Basically, the loop checks if you insert a 5 character word, and if you do, it compares the word with the characters of the tuple. If 1 or more characters are correct, it will print the correct characters, and the ones which haven't been guessed are masked with a symbol, for example '*'.

The confusing part is where I have to check if the entered word has characters that match the tuple and then print out the correct characters.

So for example:

Give a word of 5 characters: Python
Wrong!
Give a word of 5 characters: Candy
Almost there! The word is "C*d*c"
Give a word of 5 characters: Denim
Almost there! The word is "C*dec"
Give a word of 5 characters: Codec
You found the word!

Any help would be greatly appreciated.

Upvotes: 1

Views: 1114

Answers (1)

BlueSheepToken
BlueSheepToken

Reputation: 6169

Your problem is you do not print your word correctly, and your print is outside of the while, here is an answer you can try

word_tuple = ("c", "o", "d", "e", "c")

# We use this list to keep in memory the letters found
found = [False] * len(word_tuple)

word = ""

# The `all` method return True only if the list contains only True values
# Which means, while all letters are not found

while not all(found):
    # the `lower` method allows you to not take in account the uppercases
    word = input("Give a word of " +  str(len(word_tuple)) + " characters: ").lower()

    if len(word) == len(word_tuple):
        for charac in word_tuple:
            if charac in word:
                found = [b or word_tuple[index] in word for index, b in enumerate(found)]
        # The `any` method return True only if the list contains at least one True value
        # Which means we print Wrong only if there is no letter found
        if not any(found):
            print('Wrong!')
        else:
            print('Almost there! The word is "', end='')
            for i in range(len(word_tuple)):
                if found[i]:
                    print(word_tuple[i], end="")
                else:
                    print('*', end='')
            print('"')

    else:
        print('Wrong!')
# The method `join` allows you to join every string of an iterable
# Which means it joins every character of your tuple to a printable string
while word != ''.join(word_tuple):
    print('Close, try again')
    word = input("Give a word of " +  str(len(word_tuple)) + " characters: ").lower()

print('You found the word!')

An exercise can be to refactor this code in different methods

Upvotes: 2

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