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pythonpysparktimestampunix-timestampapache-spark-sql
Ticoincoin
Ticoincoin

Reputation: 209

How do I convert timestamp to unix format with pyspark

I have a dataframe with timestamp values, like this one: 2018-02-15T11:39:13.000Z I want to have it in UNIX format, using Pyspark.

I tried something like data = datasample.withColumn('timestamp_cast', datasample['timestamp'].cast('date')) but I lose a lot of information, since I only get day/month/year when I have milliseconds information in my source.

Result: 2018-02-15

Any idea to get unix format and keep precision? Thank you!

Upvotes: 11

Views: 18448

Answers (2)

Ric S
Ric S

Reputation: 9247

Another possible method is to directly cast the column to integer

df.withColumn('timestamp_unix', F.col('timestamp').cast('int'))

Upvotes: 0

Tanjin
Tanjin

Reputation: 2452

You can use the built in unix_timestamp the following ways:

from pyspark.sql.functions import unix_timestamp
df = df.withColumn('unix', unix_timestamp('timestamp'))

Or

df = df.selectExpr('unix_timestamp(timestamp)')

Upvotes: 16

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