CODEWITHSUNDEEP
javascriptphpjqueryajaxhtml
Jerad
Jerad

Reputation: 211

Insert two IDs in database

Ajax :

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>

<script>
$(document).ready(function(){

    $("#button").click(function(){
        var insPer =$("#insPer").val();
        var insPos =$("#insPos").val();
        $.ajax({
            url:'../validate/inspire.php',
            method:'POST',
            data:{
                u_id:insPer,
                p_id:insPos
            },
            success:function(data){
                //alert(data);
            }
        });
    });
});
</script>

This is my input and button

<span class="views" data-toggle="tooltip" title="Inspired">
  <input type="hidden" id="insPer<?php echo $p_id; ?>" name="insPer"> 
  <input type="hidden" id="insPos<?php echo $p_id; ?>" name="insPos">
  <a href="#" role="button" id="button<?php echo $p_id; ?>" type="submit">
    <img src="../images/lightbulb-regular.svg" class="like-btn-svg">
  </a>
</span>

Here input id comes from looping each post. The id values changing like example : 

loop1 {insPer1,insPos1,button1},  
loop2 {insPer2,insPos2,button2},

I'm passing these IDs in ajax but that id values are not changing.

Upvotes: 0

Views: 62

Answers (1)

Kagiso Marvin Molekwa
Kagiso Marvin Molekwa

Reputation: 979

try setting the hidden elements' value using the value attribute...

<span class="views" data-toggle="tooltip" title="Inspired">
    <input type="hidden" id="insPer" name="insPer" value="<?php echo $p_id; ?>" /> 
    <input type="hidden" id="insPos" name="insPos" value="<?php echo $p_id; ?>" /> <-- assuming $p_id should be the value of this input element -->

    <a href="#" role="button" id="button" type="submit">
        <img src="../images/lightbulb-regular.svg" class="like-btn-svg">
    </a>
</span>

Upvotes: 1

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