Reputation: 311
What's the easiest way to scrape just the text from a handful of webpages (using a list of URLs) using BeautifulSoup? Is it even possible?
Best, Georgina
Upvotes: 6
Views: 6482
Reputation: 56624
import urllib2
import BeautifulSoup
import re
Newlines = re.compile(r'[\r\n]\s+')
def getPageText(url):
# given a url, get page content
data = urllib2.urlopen(url).read()
# parse as html structured document
bs = BeautifulSoup.BeautifulSoup(data, convertEntities=BeautifulSoup.BeautifulSoup.HTML_ENTITIES)
# kill javascript content
for s in bs.findAll('script'):
s.replaceWith('')
# find body and extract text
txt = bs.find('body').getText('\n')
# remove multiple linebreaks and whitespace
return Newlines.sub('\n', txt)
def main():
urls = [
'http://www.stackoverflow.com/questions/5331266/python-easiest-way-to-scrape-text-from-list-of-urls-using-beautifulsoup',
'http://stackoverflow.com/questions/5330248/how-to-rewrite-a-recursive-function-to-use-a-loop-instead'
]
txt = [getPageText(url) for url in urls]
if __name__=="__main__":
main()
It now removes javascript and decodes html entities.
Upvotes: 6
Reputation: 3402
I know that it is not an answer to your exact question (about BeautifulSoup) but a good idea is to have a look at Scrapy which seems to fit yous needs.
Upvotes: 1
Reputation: 16625
It is perfectly possible. Easiest way is to iterate through list of URLs, load the content, find the URLs, add them to main list. Stop iteration when enough pages are found.
Just some tips:
urllib2.urlopen
for fetching contentBeautifulSoup
: findAll('a') for finding URLsUpvotes: 1