Reputation: 1519
I'm trying to get all the parent nodes that contain the .export
class, any children node that has a parent with the .export
the class should be skipped from the selection.
The nodes could appear anywhere in the tree but want any node that doesn't have a parent with that same class.
Having the following HTML structure:
<div class="export"> <!-- Select this one -->
<div class="export"> <!-- SKIP this one -->
<!-- Content -->
</div>
</div>
<div class="export"> <!-- Select this one -->
<!-- Some more content -->
</div>
Upvotes: 0
Views: 62
Reputation: 67505
You could get them using the jQuery .not()
method like:
console.log($(".export").not(".export .export").length);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="export">
<!-- Select this one -->
<div class="export">
<!-- SKIP this one -->
<!-- Content -->
</div>
</div>
<div class="export">
<!-- Select this one -->
<!-- Some more content -->
</div>
Upvotes: 1
Reputation: 15
You can use :not()
selector for query to skip that matches the query in the selector.
$('.export:not(.export >)')
Upvotes: 0