Reputation: 14147
Is there a way in (Gnu) sed
to replace all characters in a matching part of a string? For example I might have a list of file paths with several (arbitrary number of) paths in each line, e.g.:
/a/b/c/d/e /f/g/XXX/h/i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
/z/XXX/a/b /c/d/e/f
I would like to replace all the slashes in paths containing XXX keping all the others untouched, e.g.:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
Unfortunately I cannot come up with a solution. Maybe it's even impossible with sed
. But I'm curious if somebody find a way to solve the problem.
Upvotes: 0
Views: 124
Reputation: 30968
We can replace any /
preceding XXX
with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#\1!
It's a very similar substitution for those that follow XXX
.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#\1!
s!(XXX[^ ]*)/!\1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&\n/g' \
| sed -e '/XXX/y,/,#,' \
| sed -e ':a;/ $/{N;s/\n//;ba}'
Upvotes: 2