CODEWITHSUNDEEP
pythonpython-3.xlistdictionary
Devilhorn
Devilhorn

Reputation: 102

Inverted Index Python

I'm trying to create a dictionary of the form:

{: [ , {}]}

For example:

d = {term: [number, {number1: number2}]}

I tried to create the dictionary inside but I'm new and I couldn't understand how it's possible. The problem is that I want the form of d and I want to update number or the dictionary that contains number1 as key and number2 as value when finding term.

So the question is: Is it possible to create a dictionary like d ? And if so, how can I access term, number and the inside dictionay?

Upvotes: 1

Views: 188

Answers (2)

kantal
kantal

Reputation: 2407

d = {"term": [5, {6: 7}]}

The key's value is a list:

d["term"]   
[5, {6: 7}]

The list 's 1st element:

d["term"][0]
5

The list 's second element is a dictionary:

d["term"][1]
{6: 7}

The value of the dictionary's key '6' is 7:

d["term"][1][6]
7

Edit: Some examples for modification:

d = {"term": [5, {6: 7}]}

d["term"].append(10)
print(d)
Out: {'term': [5, {6: 7}, 10]}

l=d["term"]
l[0]=55
print(d)
Out: {'term': [55, {6: 7}, 10]}

insidedict=l[1]
print(insidedict)
{6: 7}

insidedict[66]=77
print(d)
{'term': [55, {6: 7, 66: 77}, 10]}

Upvotes: 1

jpp
jpp

Reputation: 164693

Sure, just define it as you have:

d = {'term': [5, {6: 7}]}

Since your dictionary has just one key, you an access the key via:

key = next(iter(d))

You can then access the value 5 via a couple of ways:

number = d[key][0]
number = next(iter(d.values()))[0]

Similarly, you can access the inner dictionary via either:

inner_dict = d[key][1]
inner_dict = next(iter(d.values()))[1]

And repeat the process for inner_dict if you want to access its key / value.

Upvotes: 1

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