Reputation: 5464
I have like follow table.
And I want to select match this-> "Tip-1 = 225 and Tip-2 = 65 and Tip3 = 16" product.
There are 1 products that match the query. The product ID 2.
But I do not know how to do please help me.
id product_id option_id name label value
44 1 4 Tip-5 Tip 5 Dört Mevsim
42 1 2 Tip-2 Tip 2 65
48 2 4 Tip-5 Tip 5 Dört Mevsim
47 2 3 Tip-3 Tip 3 16
46 2 2 Tip-2 Tip 2 65
45 2 1 Tip-1 Tip 1 225
52 3 4 Tip-5 Tip 5 Dört Mevsim
51 3 3 Tip-3 Tip 3 16
50 3 2 Tip-2 Tip 2 75
49 3 1 Tip-1 Tip 1 215
60 4 4 Tip-5 Tip 5 Dört Mevsim
58 4 2 Tip-2 Tip 2 75
64 5 4 Tip-5 Tip 5 Dört Mevsim
63 5 3 Tip-3 Tip 3 12
62 5 2 Tip-2 Tip 2 85
61 5 1 Tip-1 Tip 1 155
59 4 3 Tip-3 Tip 3 16
43 1 3 Tip-3 Tip 3 16
41 1 1 Tip-1 Tip 1 205
57 4 1 Tip-1 Tip 1 205
72 6 4 Tip-5 Tip 5 Dört Mev
Upvotes: 1
Views: 310
Reputation: 107696
A regular group by with OR clauses and HAVING should do it
SELECT product_id
FROM yourtable
WHERE (name = 'Tip-1' and value = '225')
OR (name = 'Tip-2' and value = '65')
OR (name = 'Tip-3' and value = '16')
GROUP BY product_id
HAVING COUNT(distinct value) = 3
Upvotes: 0
Reputation: 198314
First of all, unless you have a very specific need, this is a horrible database design. That said,
SELECT T1.product_id
FROM mytable T1
JOIN mytable T2 ON T1.product_id = T2.product_id
JOIN mytable T3 ON T1.product_id = T3.product_id
WHERE T1.name = 'Tip-1' AND T1.value = '255'
AND T2.name = 'Tip-2' AND T2.value = '65'
AND T3.name = 'Tip-3' AND T3.value = '16'
Upvotes: 0
Reputation: 765
It would be better to have own table for product details but to do your select try this
SELECT * FROM table_name WHERE (name = "Tip-1" AND value = 225) AND (name = "Tip-2" AND value = 65) AND (name = "Tip-3" AND value = 16) GROUP BY product_id
This might work but the table structure is really terrible, you should chane it if it's possible..
Upvotes: 0
Reputation: 838006
Try this:
SELECT product_id
FROM yourtable
WHERE (name, value) IN (('Tip-1', '225'), ('Tip-2', '65'), ('Tip-3', '16'))
GROUP BY product_id
HAVING COUNT(*) = 3
This assumes that (product_id, name) is unique. If not, use COUNT(DISTINCT name)
instead.
Upvotes: 3