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pythonfloating-pointtype-conversionintvalueerror
Nishant Kadivar
Nishant Kadivar

Reputation: 57

Why does int('.0') give ValueError?

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

Upvotes: 0

Views: 924

Answers (3)

U13-Forward
U13-Forward

Reputation: 71570

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1
0.1
>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')
Traceback (most recent call last):
  File "<pyshell#1>", line 1, in <module>
    int('3.1')
ValueError: invalid literal for int() with base 10: '3.1'

Upvotes: 0

Dani Mesejo
Dani Mesejo

Reputation: 61910

From the documentation of int:

If x is not a number or if base is given, then x must be a string, bytes, or bytearray instance representing an integer literal in radix base. Optionally, the literal can be preceded by + or - (with no space in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

Upvotes: 3

Kireeti K
Kireeti K

Reputation: 1520

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

Upvotes: 2

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