Reputation: 67
In this code I have several querys for user input. If there is an invalid input like 'r' instead of 4, I want my programm to say "invalid input" and ask for another user input. I tried a lot but I couldn't get it to work. I commented the problematic locations in the code. Thanks for help.
#include <stdio.h>
int main()
{
double Operand1;
double Operand2;
int Menuchoice;
int Input;
char Dummy;
double Result;
do
{
printf("Simple Calculator\n");
printf("========================\n");
printf("\n");
printf("1. Addition\n");
printf("2. Subraction\n");
printf("3. Multiplication\n");
printf("4. Division\n");
printf("9. Quit\n");
Input = scanf("%i", &Menuchoice); // At this point I want to check if there is a valid input and
do scanf("%c", &Dummy); // if not the programm should ask again
while (Dummy != '\n');
if(Input)
{
switch(Menuchoice)
{
case 1: printf("Type in the first operand:\n");
scanf("%lf", &Operand1) // Here I want to validate the input
printf("Type in the second operand:\n"); // again and the programm should also ask
scanf("%lf", &Operand2) // again if it was invalid
printf("%lf + %lf = %lf\n", Operand1, Operand2, Result);
break;
case 2:
case 3:
case 4:
default: printf("No valid input!\n");
break;
}
}
}while (Menuchoice != 9);
return 0;
}
Upvotes: 1
Views: 568
Reputation: 6384
Manual page of scanf
:
On success, these functions return the number of input items successfully matched and assigned; this can be fewer than provided for, or even zero, in the event of an early matching failure.
So here is a sample which could lead you to solve your problem:
#include <stdio.h>
int main (int argc, char* argv)
{
double o;
int res;
// To illustrate, I chose to set up an infinite loop.
// If the input is correct, we'll "break" it
while(1)
{
printf("Enter a double: ");
res = scanf("%lf",&o);
// Success = 1 read input
if (res == 1)
{
printf("Yahoo, got it right: %f\n",o);
break; // We exit the loop
}
// Ah, we failed
printf("Please retry.\n");
// popping the CR character to avoid it to be got by the next scanf()
getchar();
// Here we go for another loop.
}
// Good, we got our double.
printf("Hey, sounds like we got outside this infinite loop.\n");
}
Example:
user@so:~$ ./a.out
Enter a double: r
Please retry.
Enter a double: f
Please retry.
Enter a double: 6.543
Yahoo, got it right: 6.543000
Keep in mind this check is not perfect. For example, "frg6sgg"
will success and be displayed as 6.0000000
by printf()
.
Upvotes: 2