Reputation: 49
I have a collection of objects in this array and I need to order them by the 'order' key (asc). Is there a way to sort the objects inside the array and then return the whole array? I am relying on the order as I'm using it in a v-for with a :key.
[
{
"id":0,
"type":"Header",
"order":1,
"props":{
"order":0,
"id":0,
"section_id":0
},
"data":{
"header":""
},
"component":"header-block"
},
{
"id":1,
"type":"Header",
"order":0,
"props":{
"order":1,
"id":1,
"section_id":0
},
"data":{
"header":""
},
"component":"header-block"
}
],
[
//Another collection of objects
]
I am currently doing this -
getters: {
sorted: state => {
return _.orderBy(state.experience_sections, function(block) {
if(block.experience_blocks[0]) {
return block.experience_blocks[0].order;
}
});
}
}
The solution above does not seem to order the objects by 'asc' order. Am I on the right track?
Thanks!
P.S. Stack is telling me that is a possible duplicate question but I'm at a loss after hours of searching. My apologies if I missed an already answered question.
Upvotes: 2
Views: 4897
Reputation: 662
Deep sorting using lodash
const sortedArray = _.orderBy(items, [(item) => {
const nestedObj = _.get(item, 'props');
item['props'] = _.orderBy(nestedObj,'order','desc');
return item['order'];
}], 'desc');
Upvotes: 0
Reputation: 18515
You should also consider orderBy
method from lodash since you could easily change from asc
to desc
sort order if you would want to at a later date or have it via a variable being passed through the UI etc:
const data = [ [{ "id": 0, "type": "Header", "order": 1, "props": { "order": 0, "id": 0, "section_id": 0 }, "data": { "header": "" }, "component": "header-block" }, { "id": 1, "type": "Header", "order": 0, "props": { "order": 1, "id": 1, "section_id": 0 }, "data": { "header": "" }, "component": "header-block" } ], [{ "id": 0, "type": "Header", "order": 2, "props": { "order": 0, "id": 0, "section_id": 0 }, "data": { "header": "" }, "component": "header-block" }, { "id": 1, "type": "Header", "order": 1, "props": { "order": 1, "id": 1, "section_id": 0 }, "data": { "header": "" }, "component": "header-block" } ] ]
console.log('asc:', _.map(data, x => _.orderBy(x, 'order'))) // asc order
console.log('desc:', _.map(data, x => _.orderBy(x, 'order', 'desc'))) // desc
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>
Upvotes: 2
Reputation: 432
Will sort each subarray in an array
const sortedArr = _.map(arr, subArray => _.sortBy(subArray, "order"));
Upvotes: 1
Reputation: 4184
Just in case you want plain javascript solution.. using Array.forEach
I have also extended your array to contain more data
var arr = [[
{
"id":0,
"type":"Header",
"order":1,
"props":{
"order":0,
"id":0,
"section_id":0
},
"data":{
"header":""
},
"component":"header-block"
},
{
"id":1,
"type":"Header",
"order":0,
"props":{
"order":1,
"id":1,
"section_id":0
},
"data":{
"header":""
},
"component":"header-block"
}
], [
{
"id":0,
"type":"Header",
"order":2,
"props":{
"order":0,
"id":0,
"section_id":0
},
"data":{
"header":""
},
"component":"header-block"
},
{
"id":1,
"type":"Header",
"order":1,
"props":{
"order":1,
"id":1,
"section_id":0
},
"data":{
"header":""
},
"component":"header-block"
}
]]
arr.forEach(d => d.sort((a,b) => a.order - b.order))
console.log(arr)
Upvotes: 2