Matt
Matt

Reputation: 79

Why do you not have to return objects in Python?

I am a newbie to Python and programming in general and I have just gotten into OOP. In Python, whatever is defined in a function's namespace is only valid while inside that namespace; once outside that space things like variables are forgotten:

def foo():
    a = 3

print(a)

NameError: name 'a' is not defined

As far as I know, besides returning data from functions, any information inside the function is lost at the end of the function call, and therein lies my question. Take the following code:

class Example:

    def __init__(self, name):
        self.name = name

    def foo(self):
        self.name = 'John'

bar = Example('Jake')
bar.foo()
print(bar.name)

'John'

My question is: why don't you have to return objects after methods? In normal functions any variables are forgotten, but in methods it seems data is actually appended to the object itself, such as the foo() method being able to reference self.name despite self.name first being referenced in another method. Is this correct? Or is there a better technical explanation?

Upvotes: 6

Views: 5510

Answers (5)

shiv_90
shiv_90

Reputation: 1097

Well, this is what is called as 'scoping' in OOP. And though the difference between classes and functions might seem subtle, it makes a big difference.

Simply said, functions rely on global and local variables. Global variables are objects that you define in the global workspace. This is like having a workbench and getting to use a common object across your functions and classes that you define. And so, for example, if you modify your function foo() to include an argument, like so:

a = 3 # This is globally defined

def foo(a):
  a = 3 * a
  return a

print(foo(a))
9

Changing the global value of a to something like 2 will give you 6 as the answer. We 'return' an object because it is locally defined within the scope of a function. In this example above, foo() performs the local operation 3 * a and defines it locally to a itself and returns it. And so you can also skip the global variable a when executing foo() and define it locally within the function scope:

print(foo(6)) # Locally defined
18

print(a)
3 # Returns global variable

Classes on the other hand need to be declared and that has been very nicely explained by members (see above).

Upvotes: 1

ba_ul
ba_ul

Reputation: 2209

Welcome to Stack Overflow. You are thinking in the right direction. I'll start at a more basic level so that other beginner viewers can understand what is going on.

Think of Example as a template for creating new objects of a certain kind -- meaning the objects will all have the same attributes (also known as properties) and functionalities. For example, by drawing an analogy with real-life objects, all cars have the attribute "speed" and the functionality "accelerate".

The attribute values will be specific to the objects. For example, one car will have 0 mph speed and another 70 mph.

The attribute values at any point describe the state of an object. Methods, which you can think of as the object's functionalities, allow the ability to change an object's state.

bar is an object that you created using the template (that is, class) Example. If you have to describe this object's state, you'd tell us the values of its attributes. In this case, the object has only one attribute: name.

Now, this is the important part: name is not just any variable, it's an attribute of any object you make from the class Example. Think of name as always attached to the object. That's why you wrote self.name = 'John' and not name = 'John'. In the latter case, name would not be a part of the object bar, and no other method in the class would have access to the name variable.

So, to summarize, when you have created an object out of a class, think of the object as having various attributes. All the methods, or functionalities, of the object will have access to all those attributes. The values of the attributes would describe, at any point, the object's state at that moment. It is through that object's methods that one would change its state.

Finally, here's a great tool to visualize what happens at each line of your code: pythontutor.com

Upvotes: 2

rohit-biswas
rohit-biswas

Reputation: 845

There isn't a lot of difference between methods and functions (See this thread for details)

Though one important distinction, that you might have immediately noticed, is that methods have self as their first argument and we say that method foo is "bound" to instance bar of class Example, meaning simply that foo will be called with its first argument (self) as the instance (bar) itself

With this knowledge lets see what the following function does:

class Example:

  def __init__(self, name):
    self.name = name

  def foo(self):
    self.name = 'John'

bar = Example('Jake')

In method init, you assign name to self. But what is self? It is bar itself, so calling init can be thought of as doing

bar.name = 'Jake'

Then when you called method foo

bar.foo()

You equivalently did

bar.name = 'John'

So, it should not be surprising when finally the output of the following was 'John'

print(bar.name)  # John

About your query regarding methods not having to return anything, it is not quite so. Methods and functions may or may not return anything as (See this answer). But in this context, what is happening is an object passed to a method is being manipulated (self, which is bar, is being assigned a name) and because the object is alive after the method call completes, we can observe the changes done by the method (ie, we can see that bar.name is changed to 'John')

This works works with functions as well:

def another_foo(self):
  self.name = 'Mark'
baz = Example('Jake')
another_foo(baz)
print(baz.name)  # Mark

You see, this function did not return anything either. It worked just like the method foo by manipulating its argument. In fact, you could add it to the Example class and use it like a method

Example.another_foo = another_foo
new_bar = Example('Jake')
print(new_bar.name)  # Jake
new_bar.another_foo()
print(new_bar.name)  # Mark

Upvotes: 3

Piyush Saravagi
Piyush Saravagi

Reputation: 369

To understand this you will need to understand how self works. You can learn more here: Understanding self in python

In a nutshell, self refers to the calling object. Invoking self.variable refers to the variable associated with the calling object. Python is smart enough to create one if it doesn't exist.

Calling self.variable inside a class is the same as calling object.variable with your object reference

Consider the following example to prove this:

class Example:
    def print_x(self):
        print(self.x)

obj = Example()
obj.x = 5;    # Create a new attribute of the object and assign it a value 5
print(obj.x)  # Outputs 5
obj.print_x() # Outputs 5

In your example, I've added a couple of print statements to help you understand the state of the program during the execution:

    class Example:
    def __init__(self, name):
        print(dir(self)) # Printing object contents before initializing name
        self.name = name # New attribute 'name' created
        print(dir(self)) # Printing object contents after initializing name

    def foo(self):
        print("Before foo, self.name = "+ self.name)
        self.name = 'John'
        print("After foo, self.name = "+ self.name)


bar = Example('Jake')
bar.foo()
print(bar.name)

The output of the above code is

['__doc__', '__init__', '__module__', 'foo']
['__doc__', '__init__', '__module__', 'foo', 'name']
Before foo, self.name = Jake
After foo, self.name = John
John

I will walk you through this code. When we first create bar, the __init__() method is called. Here we print the contents of the object using dir(self). The output ['__doc__', '__init__', '__module__', 'foo'] indicates that the object has only one member, the 'foo' method.

Now we create a new attribute called 'name' and assign it the value 'Jake'. Thus the object now has another member, the 'name' attribute as seen by the output of the next dir(self) ['__doc__', '__init__', '__module__', 'foo', 'name']

Now we call the foo method and print the value before and after the method. Before the name is changed in foo, the value of name associated with the object is "Jake". However, after the name is changed, the value of self.name is "John". This is indicated by

Before foo, self.name = Jake
After foo, self.name = John`

We next verify that the change made by changing self.name has indeed changed the value of name in bar by printing bar.name which gives us the expected output, John

Now coming back to your question, self.name is not an ordinary variable inside some method that is lost when we are out of scope. self can be used essentially anywhere inside the class to refer to the calling object (bar in this case). It is used to manipulate this calling object. Now since bar is within the scope, we are able to print its name attribute.

In normal functions any variables are forgotten but in methods it seems data is actually appended to the object itself

self manipulates the attributes in the object and is not limited to the scope of the method.

Upvotes: 4

Dinari
Dinari

Reputation: 2557

First, you don't have to return a value in a method, not in python, and not in many other programming languages. for example:

def append_a(lst):
    lst.append('a')

bob = []
append_a(bob)
print(bob)
['a']

Above we do not return anything in the function, but we use it to modify an existing data structure, this is very common almost anywhere.

Secondly, in your second example, you created an instance of the class Example, when you look at self.something you are looking at a member of the class, unlike other languages, where often members are only declared once, in python you can dynamically add members.
Thus when looking at bar.name you are looking at a member of the class, its value on the instance bar. If you would look at a different instance, the value will be different.

class Example:

    def __init__(self, name):
        self.name = name

    def foo(self):
        self.name = 'John'

bar = Example('Jake')
bob = Example('Bob')
bar.foo()
print(bar.name)
print(bob.name)

John
Bob

Upvotes: 5

Related Questions