CODEWITHSUNDEEP
pythonencryptionhashsha256hashlib
Zohar81
Zohar81

Reputation: 5106

Hexify sha digest result without using hashlib

I've got digest value of data in string format, and I'd like to hexify it.

Here's the sample string '\xf0z\xd8[\xfc\x7f'

However, I cannot use hashlib since I don't have the original data from which the hash was created from.

trying .digesthex() on the string wouldn't work since str object don't have that method. Is there any alternative ?

Upvotes: 0

Views: 90

Answers (1)

ottomeister
ottomeister

Reputation: 5818

For each character in the original string, use ord to obtain the numeric value of the character and then use a string format operation to express that numeric value as a string containing a pair of hex digit characters. Accumulate those two-digit strings into a single string.

    mystring = '\xf0z\xd8[\xfc\x7f'
    result = ''
    for ch in mystring:
        number = ord(ch)
        hexdigits = '{:02x}'.format(number)
        result += hexdigits
    print result

You can do all of that on one line by using a list comprehension to collect the pairs of hex digit strings into a list and then using the join method with an empty separator string to glue the hex digit strings together into a single string.

    mystring = '\xf0z\xd8[\xfc\x7f'
    result   = ''.join([ '{:02x}'.format(ord(ch)) for ch in mystring ])
    print result

Or instead of a list comprehension you can use map with a lambda to build the list of hex digit pairs.

    mystring = '\xf0z\xd8[\xfc\x7f'
    result   = ''.join(map(lambda ch: '{:02x}'.format(ord(ch)), mystring))
    print result

The map version is harder to read but it might run slightly faster.

Upvotes: 1

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