Reputation: 9028
I have an array of objects, I would like to remove duplicates.
My array has a common field name
that I would like to use for deduplication.
I am trying to convert the array to a map and then from map back to array but map conversions gives me an error duplicate field name: "a"
:
local arr = [
{ "name": "a", "value": 1234},
{ "name": "b", "value": 555},
{ "name": "c", "value": 0},
{ "name": "a", "value": 1234}
];
local map = { [x.name] : x for x in arr };
Desired output:
[
{ "name": "a", "value": 1234},
{ "name": "b", "value": 555},
{ "name": "c", "value": 0}
]
Upvotes: 1
Views: 3587
Reputation: 9028
As @seh pointed out in ksonnet channel, the latest jsonnet release now allows to use std.set()
on objects.
local arr = [
{ name: "a", value: 1234 },
{ name: "b", value: 555 },
{ name: "c", value: 0 },
{ name: "a", value: 1234 },
];
std.set(arr, function(o) o.name)
The std.set()
header is documented in jsonnet's std lib implementation.
Upvotes: 2
Reputation: 3020
You can implement it by replacing the comprehension with std.foldl()
, do note though the ordering issue:
local arr = [
{ name: "a", value: 4321 },
{ name: "b", value: 555 },
{ name: "c", value: 0 },
{ name: "a", value: 1234 },
];
// Use foldl to iterate from array, can't use comprehension because of dup fields
local map = std.foldl(function(x, y) x { [y.name]: y }, arr, {});
// Re-convert map to array, note that it'll not respect original order
// but fields' (ie 'name' key)
[ map[x] for x in std.objectFields(map)]
If you need to keep original sort order in output array, you can then add an _idx
field to use in a final sort()
:
local arr = [
{ name: "a", value: 4321 },
{ name: "b", value: 555 },
{ name: "c", value: 0 },
{ name: "a", value: 1234 },
];
// Overload array elements with there index (`_idx` field)
local idxArray = std.mapWithIndex(function(i, x) x { _idx:: i }, arr);
// Use foldl to iterate from array, can't use comprehension because of dup fields
local map = std.foldl(function(x, y) x { [y.name]: y }, idxArray, {});
// Re-convert map to array, it'll keep original order via added _idx field
std.sort([map[x] for x in std.objectFields(map)], function(e) e._idx)
Upvotes: 1