How do I create an enum from an Int in Kotlin?

Question

I have this enum:

enum class Types(val value: Int) {
    FOO(1)
    BAR(2)
    FOO_BAR(3)
}

How do I create an instance of that enum using an Int?

I tried doing something like this:

val type = Types.valueOf(1)

And I get the error:

Integer literal does not conform to the expected type String

Answer 1

I think another solution might be clearer, it's possible to use a String to initialize the enum.

It's better human-readable and can be seen right away what the enum value is.

For example:

enum class Planet {
    EARTH,
    MARS,
    VENUS
}

Then we can initialize it like this:

val mars = Planet.valueOf("MARS")

Answer 2

It really depends on what you actually want to do.

• If you need a specific hardcoded enum value, then you can directly use Types.FOO
• If you are receiving the value dynamically from somewhere else in your code, you should try to use the enum type directly in order not to have to perform this kind of conversions
• If you are receiving the value from a webservice, there should be something in your deserialization tool to allow this kind of conversion (like Jackson's @JsonValue)
• If you want to get the enum value based on one of its properties (like the value property here), then I'm afraid you'll have to implement your own conversion method, as @Zoe pointed out.

One way to implement this custom conversion is by adding a companion object with the conversion method:

enum class Types(val value: Int) {
    FOO(1),
    BAR(2),
    FOO_BAR(3);

    companion object {
        private val types = values().associate { it.value to it }

        fun findByValue(value: Int): Types? = types[value]
    }
}

Companion objects in Kotlin are meant to contain members that belong to the class but that are not tied to any instance (like Java's static members). Implementing the method there allows you to access your value by calling:

var bar = Types.findByValue(2) ?: error("No Types enum value found for 2")

Note that the returned value is nullable, to account for the possibility that no enum value corresponds to the parameter that was passed in. You can use the elvis operator ?: to handle that case with an error or a default value.

Answer 3

Protocol orientated way with type-safety

interface RawRepresentable<T> {
    val rawValue: T
}

inline fun <reified E, T> valueOf(value: T): E? where E : Enum<E>, E: RawRepresentable<T> {
    return enumValues<E>().firstOrNull { it.rawValue == value }
}

enum class Types(override val rawValue: Int): RawRepresentable<Int> {
    FOO(1),
    BAR(2),
    FOO_BAR(3);
}

Usage

val type = valueOf<Type>(2) // BAR(2)

You can use it on non-integer type, too.

Answer 4

Another option...

enum class Types(val code: Int) {
    FOO(1),
    BAR(2),
    FOO_BAR(3);

    companion object {
        val map = values().associate { it.code to it }

        // Get Type by code with check existing codes and default
        fun getByCode(code: Int, typeDefault_param: Types = FOO): Types {
            return map[code] ?: typeDefault_param
        }
    }
}

fun main() {
    println("get 3: ${Types.getByCode(3)}")
    println("get 10: ${Types.getByCode(10)}")
}

get 3: FOO_BAR
get 10: FOO

Answer 5

Enum#valueOf is based on name. Which means in order to use that, you'd need to use valueof("FOO"). The valueof method consequently takes a String, which explains the error. A String isn't an Int, and types matter. The reason I mentioned what it does too, is so you know this isn't the method you're looking for.

If you want to grab one based on an int value, you need to define your own function to do so. You can get the values in an enum using values(), which returns an Array<Types> in this case. You can use firstOrNull as a safe approach, or first if you prefer an exception over null.

So add a companion object (which are static relative to the enum, so you can call Types.getByValue(1234) (Types.COMPANION.getByValue(1234) from Java) over Types.FOO.getByValue(1234).

companion object {
    private val VALUES = values()
    fun getByValue(value: Int) = VALUES.firstOrNull { it.value == value }
}

values() returns a new Array every time it's called, which means you should cache it locally to avoid re-creating one every single time you call getByValue. If you call values() when the method is called, you risk re-creating it repeatedly (depending on how many times you actually call it though), which is a waste of memory.

Admittedly, and as discussed in the comments, this may be an insignificant optimization, depending on your use. This means you can also do:

companion object {
    fun getByValue(value: Int) = values().firstOrNull { it.value == value }
}

if that's something you'd prefer for readability or some other reason.

The function could also be expanded and check based on multiple parameters, if that's something you want to do. These types of functions aren't limited to one argument.

Answer 6

This is for anyone looking for getting the enum from its ordinal or index integer.

enum class MyEnum { RED, GREEN, BLUE }
MyEnum.values()[1] // GREEN

Another solution and its variations:

inline fun <reified T : Enum<T>> enumFromIndex(i: Int) = enumValues<T>()[i]
enumFromIndex<MyEnum>(1) // GREEN

inline fun <reified T : Enum<T>> enumFromIndex(i: Int) = enumValues<T>().getOrNull(i)
enumFromIndex<MyEnum>(3) ?: MyEnum.RED // RED

inline fun <reified T : Enum<T>> enumFromIndex(i: Int, default: T) =
    enumValues<T>().getOrElse(i) { default }
enumFromIndex(2, MyEnum.RED) // BLUE

It is an adapted version of another answer. Also, thanks to Miha_x64 for this answer.

Answer 7

If you hate declaring for each enum type a companion object{ ... } to achieve EMotorcycleType.fromInt(...). Here's a solution for you.

EnumCaster object:

object EnumCaster {
    inline fun <reified E : Enum<E>> fromInt(value: Int): E {
        return enumValues<E>().first { it.toString().toInt() == value }
    }
}

Enum example:

enum class EMotorcycleType(val value: Int){
    Unknown(0),
    Sport(1),
    SportTouring(2),
    Touring(3),
    Naked(4),
    Enduro(5),
    SuperMoto(6),
    Chopper(7),
    CafeRacer(8),

    .....
    Count(9999);

    override fun toString(): String = value.toString()
}

Usage example 1: Kotlin enum to jni and back

fun getType(): EMotorcycleType = EnumCaster.fromInt(nGetType())
private external fun nGetType(): Int

fun setType(type: EMotorcycleType) = nSetType(type.value)
private external fun nSetType(value: Int)

---- or ----

var type : EMotorcycleType
    get() = EnumCaster.fromInt(nGetType())
    set(value) = nSetType(value.value)

private external fun nGetType(): Int
private external fun nSetType(value: Int)

Usage example 2: Assign to val

val type = EnumCaster.fromInt<EMotorcycleType>(aValidTypeIntValue)

val typeTwo : EMotorcycleType = EnumCaster.fromInt(anotherValidTypeIntValue)

Answer 8

If you are using integer value only to maintain order, which you need to access correct value, then you don't need any extra code. You can use build in value ordinal. Ordinal represents position of value in enum declaration.

Here is an example:

enum class Types {
    FOO,               //Types.FOO.ordinal == 0 also position == 0
    BAR,               //Types.BAR.ordinal == 1 also position == 1
    FOO_BAR            //Types.FOO_BAR.ordinal == 2 also position == 2
}

You can access ordinal value simply calling:

Types.FOO.ordinal

To get correct value of enum you can simply call:

Types.values()[0]      //Returns FOO
Types.values()[1]      //Returns BAR
Types.values()[2]      //Returns FOO_BAR

Types.values() returns enum values in order accordingly to declaration.

Summary:

Types.values(Types.FOO.ordinal) == Types.FOO //This is true

If integer values don't match order (int_value != enum.ordinal) or you are using different type (string, float...), than you need to iterate and compare your custom values as it was already mentioned in this thread.

Answer 9

enum class Types(val value: Int) {
    FOO(1),
    BAR(2),
    FOO_BAR(3);

    companion object {
        fun fromInt(value: Int) = Types.values().first { it.value == value }
    }
}

You may want to add a safety check for the range and return null.

Answer 10

try this...

companion object{
    fun FromInt(v:Int):Type{
        return  Type::class.java.constructors[0].newInstance(v) as Type
    }
}

Answer 11

I would build the 'reverse' map ahead of time. Probably not a big improvement, but also not much code.

enum class Test(val value: Int) {
    A(1),
    B(2);

    companion object {
        val reverseValues: Map<Int, Test> = values().associate { it.value to it }
        fun valueFrom(i: Int): Test = reverseValues[i]!!
    }
}

Edit: map...toMap() changed to associate per @hotkey's suggestion.

Answer 12

A naive way can be:

enum class Types(val value: Int) {
    FOO(1),
    BAR(2),
    FOO_BAR(3);

    companion object {
        fun valueOf(value: Int) = Types.values().find { it.value == value }
    }
}

Then you can use

var bar = Types.valueOf(2)