Reputation: 79
I'm trying to figure out an elegant/efficient solution for finding sublists in a list, with certain constraints.
For example, given this list:
values = ['a', 'b', 'c', 'd', 'e', 'f']
And a value for maxLength:
maxLength = 4
Find all sublists in the values list such that:
So in this example, these are acceptable solutions:
[['a'], ['b'], ['c'], ['d'], ['e'], ['f']]
[['a', 'b'], ['c'], ['d'], ['e'], ['f']]
...
[['a', 'b'], ['c', 'd', 'e'], ['f']]
...
[['a', 'b', 'c', 'd'], ['e', 'f']]
...
[['a', 'b'], ['c', 'd', 'e', 'f']]
These are not acceptable:
[['a', 'b'], ['d', 'e'], ['f']] #Error: not consecutive, 'c' is missing
[['a', 'b', 'c'], ['c', 'd', 'e'], ['f']] #Error: overlapping, 'c' is in two subsets
[['a', 'b', 'c', 'd', 'e'], ['f']] #Error: the first sublist has length > maxLength (4)
Upvotes: 3
Views: 945
Reputation: 71451
You can use recursion:
values = ['a', 'b', 'c', 'd', 'e', 'f']
maxLength = 4
def groupings(d):
if not d:
yield []
else:
for i in range(1, maxLength+1):
for c in groupings(d[i:]):
yield [d[:i], *c]
_d = list(groupings(values))
new_d = [a for i, a in enumerate(_d) if a not in _d[:i]]
Output:
[[['a'], ['b'], ['c'], ['d'], ['e'], ['f']], [['a'], ['b'], ['c'], ['d'], ['e', 'f']], [['a'], ['b'], ['c'], ['d', 'e'], ['f']], [['a'], ['b'], ['c'], ['d', 'e', 'f']], [['a'], ['b'], ['c', 'd'], ['e'], ['f']], [['a'], ['b'], ['c', 'd'], ['e', 'f']], [['a'], ['b'], ['c', 'd', 'e'], ['f']], [['a'], ['b'], ['c', 'd', 'e', 'f']], [['a'], ['b', 'c'], ['d'], ['e'], ['f']], [['a'], ['b', 'c'], ['d'], ['e', 'f']], [['a'], ['b', 'c'], ['d', 'e'], ['f']], [['a'], ['b', 'c'], ['d', 'e', 'f']], [['a'], ['b', 'c', 'd'], ['e'], ['f']], [['a'], ['b', 'c', 'd'], ['e', 'f']], [['a'], ['b', 'c', 'd', 'e'], ['f']], [['a', 'b'], ['c'], ['d'], ['e'], ['f']], [['a', 'b'], ['c'], ['d'], ['e', 'f']], [['a', 'b'], ['c'], ['d', 'e'], ['f']], [['a', 'b'], ['c'], ['d', 'e', 'f']], [['a', 'b'], ['c', 'd'], ['e'], ['f']], [['a', 'b'], ['c', 'd'], ['e', 'f']], [['a', 'b'], ['c', 'd', 'e'], ['f']], [['a', 'b'], ['c', 'd', 'e', 'f']], [['a', 'b', 'c'], ['d'], ['e'], ['f']], [['a', 'b', 'c'], ['d'], ['e', 'f']], [['a', 'b', 'c'], ['d', 'e'], ['f']], [['a', 'b', 'c'], ['d', 'e', 'f']], [['a', 'b', 'c', 'd'], ['e'], ['f']], [['a', 'b', 'c', 'd'], ['e', 'f']]]
Upvotes: 5