Reputation: 595
I have a dataset with column named "msg_dateStr" which contains user's accessing date and time.
I tried to split it into two different columns; date and time, and I did SELECT date(msg_dateStr, 'localtime') as Year
but it returns null straight.
I don't know why this happens and how I can make sure something went wrong.
Any advice will be appreciated.
Upvotes: 0
Views: 1990
Reputation: 56953
The date to be used by the Date and Time Functions such as date MUST be in a format that is recognised by SQLite for a useful result. Recognised formats are (extract from the link above) :-
Time Strings
A time string can be in any of the following formats:
YYYY-MM-DD YYYY-MM-DD HH:MM YYYY-MM-DD HH:MM:SS YYYY-MM-DD HH:MM:SS.SSS YYYY-MM-DDTHH:MM YYYY-MM-DDTHH:MM:SS YYYY-MM-DDTHH:MM:SS.SSS HH:MM HH:MM:SS HH:MM:SS.SSS now DDDDDDDDDD
You need to ensure that the data is saved accordingly or alternately (but not recommended at all) reformat the column via SQL (e.g. using the substr built-in function).
Upvotes: 1