CODEWITHSUNDEEP
pythonpython-3.xlistlambda
tehoo
tehoo

Reputation: 83

filtering a list of strings using lambda

I have a list like,

old_list=["a_apple","b_banana","c_cherry"]

and I want to get new list using lambda.

new_list=["apple","banana","cherry"]

I tried but it doesn't work as I expected. here is what I wrote.

new_list=filter(lambda x: x.split("_")[1], old_list)

what is the problem ?

Upvotes: 0

Views: 823

Answers (4)

Mayank Porwal
Mayank Porwal

Reputation: 34086

Try this:

Python-2:

In [978]: old_list=["a_apple","b_banana","c_cherry"]

In [980]: new_list = map(lambda x: x.split("_")[1], old_list)

In [981]: new_list
Out[981]: ['apple', 'banana', 'cherry']

Python-3:

In [4]: new_list = list(map(lambda x: x.split("_")[1], old_list))

In [5]: new_list
Out[5]: ['apple', 'banana', 'cherry']

Upvotes: 2

Srce Cde
Srce Cde

Reputation: 1824

Using list comprehensions

lst=["a_apple","b_banana","c_cherry"]
[i.split("_")[1] for i in lst]

Output:

['apple', 'banana', 'cherry']

Upvotes: 1

omri_saadon
omri_saadon

Reputation: 10669

By using lambda and map:

li=["a_apple","b_banana","c_cherry"]

new_li = map(lambda x: x.split('_')[1], li)
print (list(new_li))
# ['apple', 'banana', 'cherry']

Upvotes: 0

blhsing
blhsing

Reputation: 107095

You can map the list with a lambda function:

list(map(lambda s: s.split('_')[1], old_list))

This returns:

['apple', 'banana', 'cherry']

Upvotes: 1

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