CODEWITHSUNDEEP
c++functionstructparametersanonymous-struct
Sneppy
Sneppy

Reputation: 386

Define an anonymous struct in function call

I can already do this:

struct {
    uint64 _i;
    bool operator()(uint64 elem)
    {
        const uint64 i = _i++; return elem & i; // Just an example
    }
} filter;

// Templated function
Array<uint64> clone = Containers::filter(array, filter);

I would like to know if it is possible to move the struct definition right inside the function call, so that I could for example define a macro like this one:

Array<uint64> clone = Containers::filter(array, ENUMERATE(i, elem, elem & i)); // Same as above

When I try this I get expected primary-expression before 'struct':

Array<uint64> clone = Containers::filter(array, struct {
    uint64 _i;
    bool operator()(uint64 elem)
    {
        const uint64 i = _i++; return elem & i;
    }
});

Upvotes: 0

Views: 165

Answers (1)

Quentin
Quentin

Reputation: 63154

Your requirements can be satisfied with a stateful, mutable lambda:

Array<uint64> clone = Containers::filter(
    array,
    [_i = uint64{0}](uint64 elem) mutable -> bool {
        const uint64 i = _i++;
        return elem & i;
    }
);

Upvotes: 3

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