CODEWITHSUNDEEP
javascripthtml
user10727653
user10727653

Reputation:

showing odd numbers with javascript

I have made this guessing numbers, if one writes any other number than between 10 and 20 it will show them accordingly, but I want that it shows odd numbers.
For example, when I write 1, 2 ,3 and then 10, it will print 1, 2, 3 and 10, but I want it print every second number like this: 1, 3 and then 10 which is correct one.
I've tried many things, but couldn't make it work.

var luku;
luku = Number(prompt("number"));

while (luku < 10 || luku > 20) {
  document.write(luku + "<br>");
  luku = Number(prompt("give number"));

}
document.write(" correct " + luku);

Upvotes: 0

Views: 223

Answers (3)

Prashant Pimpale
Prashant Pimpale

Reputation: 10697

You can check before appending the number to the document like:

if ((luku % 2) !== 0){
// Then add only
}

To display every second element from an array and exist integer:

var luku;
var list = [];
luku = Number(prompt("number"));
var last;

while (luku < 10 || luku > 20) {
  last = luku;
  list.push(luku);
  luku = Number(prompt("give number"));
}
var listToDisplay = list.filter(a=>list.indexOf(a)%2===1)
listToDisplay.push(luku);
document.write(" correct " + listToDisplay);

To display Odd numbers from user input:

var luku;
var list = [];
luku = Number(prompt("number"));

while (luku < 10 || luku > 20) {
  if ((luku % 2) !== 0){
  document.write(luku + "<br>");
  }
  luku = Number(prompt("give number"));

}
document.write(" correct " + luku);

Upvotes: 1

Nikhil Aggarwal
Nikhil Aggarwal

Reputation: 28455

Try following using a counter variable which is incremented everytime in the loop and based on that (odd values) paints text.

var luku;
var counter = 1;
luku = Number(prompt("number"));

while (luku < 10 || luku > 20) {
  // paint for odd values
  if(counter%2) document.write(luku + "<br>");
  counter++;
  luku = Number(prompt("give number"));
}
document.write(" correct " + luku);

Upvotes: 3

giraffesyo
giraffesyo

Reputation: 5362

I added a switch odd which flips every time a guess happens, so it only shows the odd ones. 

let guess
let odd = true
guess = Number(prompt('number'))

while (guess < 10 || guess > 20) {
  if (odd) document.write(guess + '<br>')
  odd = !odd
  guess = Number(prompt('Enter a number'))
}
document.write(' correct ' + guess)

Upvotes: 0

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