Reputation: 2117
I have two pandas dataframes that I want to join on employee_id. One is Employee_Logs the other is HR_Data.
Employee_Logs_df
employee_id action
2325255b login
51666164 login
51666164v login
r1211 logoff
r18552421 login
HR_Data_df
employee_id name
2325255 Rob
51666164 Tom
r1211 Tammy
r18552421 Ron
I want to join them so that the data looks like this:
New_df
employee_id action name
2325255b login Rob
51666164 login Tom
51666164v login Tom
r1211 logoff Tammy
r18552421 login Ron
I could do an easy join if the employee_id field matched up on both tables, but the same user can have a "b
" or a "v
" after their employee id to specify if the account is elevated like an admin account. Some user accounts have an "r
" in front of the id but that is the case in both tables.
In SQL this gives me the desired results:
select el*,
coalesce(h.name, hv.name, hb.name) as name
from employee_logs el left join
hr_data h
on el.employee_id = h.employee_id left join
hr_data hv
on el.employee_id = concat(h.employee_id, 'v') left join
hr_data hb
on el.employee_id = concat(h.employee_id, 'b');
Is there a good way in Python where I can do some where actions and create a new df?
Upvotes: 2
Views: 386
Reputation: 51395
You can strip the trailing letter from employee_id
in Employee_Logs_df
using a regex, then map that to your names from HR_Data_df
:
new_df = Employee_Logs_df.assign(name = Employee_Logs_df.employee_id
.str.extract('(.*\d+)',expand=False)
.map(HR_Data_df.set_index('employee_id')['name']))
>>> new_df
employee_id action name
0 2325255b login Rob
1 51666164 login Tom
2 51666164v login Tom
3 r1211 logoff Tammy
4 r18552421 login Ron
You can do something very similar with a merge if you wanted:
new_df = Employee_Logs_df.merge(HR_Data_df.set_index('employee_id'),
left_on=Employee_Logs_df.employee_id
.str.extract('(.*\d+)',expand=False),
right_index=True)
>>> new_df
employee_id action name
0 2325255b login Rob
1 51666164 login Tom
2 51666164v login Tom
3 r1211 logoff Tammy
4 r18552421 login Ron
Upvotes: 3