Reputation: 1
On the UI I have a checkAll button which is implemented as a span under a div block. clicking it become hard so I used JavaScriptExcutor. I want click it two times. the code is as following 6 lines. the line3 always succeeded, but line 6 always fail silently (no error or exception, but click not happening). if I comment out line 3 then line 6 will function. why? please help me.
IJavaScriptExecutor executor = (IJavaScriptExecutor)drv;
IWebElement chkAll = TaskerStatus.FindElement(By.Id("header3-column0"));
executor.ExecuteScript("arguments[0].click();", chkAll);
cmdBar1collapseAll.Click();
expandAllBtn.Click();
executor.ExecuteScript("arguments[0].click();", chkAll);
Upvotes: 0
Views: 643
Reputation: 193208
If I have understood the usecase / issue properly, Line 6 i.e.:
executor.ExecuteScript("arguments[0].click();", chkAll);
fails silently, i.e. no error or exception and the click()
not happening as well.
But again if you comment out line 3
i.e. the first instance of:
executor.ExecuteScript("arguments[0].click();", chkAll);
Then line 6
i.e. the second instance of:
executor.ExecuteScript("arguments[0].click();", chkAll);
functions well.
The reason Line 6 is failing because when you invoked click()
on the IWebElement chkAll a JavaScript / jQuery might have been active.
You need to induce WebDriverWait for the IWebElement chkAll to be clickable before you invoke the click at Line 6 and you can update Line 6 as follows:
executor.ExecuteScript("arguments[0].click();", new WebDriverWait(driver, TimeSpan.FromSeconds(20)).Until(ExpectedConditions.ElementToBeClickable(TaskerStatus.FindElement(By.Id("header3-column0")))));
Upvotes: 2