CODEWITHSUNDEEP
regexnewlinespaces
clausnz
clausnz

Reputation: 37

Regular expression to remove spaces and replace newline separators

Is it possible to replace a character sequence with a newline (\s~\s in this example) and also remove spaces in the beginning and at the end with one regular expression? The number of lines must be flexible.

Input:

    foo = 1 ~ bar = 2 ~ baz = 3 ~ ...     <- also spaces at the end

Desired output:

foo = 1
bar = 2
baz = 3
... <- no spaces here

I got it working so far, the problem is that my result still has the spaces at the end of the last line:

My current regex search and replace (https://regexr.com/444au):

# search 
/(\s*)([^~\s]{1}.*?)(\s~\s)(?=.*)(\s*)/g

# replace
$2\n

Upvotes: 0

Views: 160

Answers (1)

CertainPerformance
CertainPerformance

Reputation: 371019

One option is to alternate between the \s~\s and \s+$, thereby matching the trailing spaces at the very end:

\s*([^~\s].*?)(?:\s~\s+|\s+$)

replace with

$1\n

https://regexr.com/4452l

Note that since the only group you actually care about is the one with [^~\s]{1}.*?, you can remove all other capturing groups. {1} is a meaningless quantifier, so you can remove that as well, and (?=.*) won't do anything - any position in the string will be followed by zero or more characters regardless, so feel free to remove that lookahead.

Upvotes: 1

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