CODEWITHSUNDEEP
pythonpython-3.x
Simon Fredrich
Simon Fredrich

Reputation: 95

Function does not modify variable in python

I create two lists, a, b with 10 random numbers from 0 to 61 and then I compare the lists if they have common numbers or not.

I store the common numbers in a separate list.

If the list does have numbers in it the commonCount is going up and if the list is empty the noCommonCount is going up.

But when I want to print the counts after I rand the function 10 times it prints out 0.

I don't know why because I declared the variables commonCount and noCommonCount outside the function.

import random

noCommonCount = 0
commonCount = 0

def list_overlap():
    a = []
    b = []

    count = 0

    while count < 10:
        count = count + 1
        a.append(random.randint(0, 61))
        b.append(random.randint(0, 61))    

    commonNumbers = []

    for i in a:
        if i in b:
            if i not in commonNumbers:
                commonNumbers.append(i)

    if not commonNumbers:
        noCommonCount + 1
    else:
        commonCount + 1


functionCount = 0

while functionCount < 10:
    functionCount = functionCount + 1
    list_overlap()

print(noCommonCount)
print(commonCount)

Upvotes: 0

Views: 195

Answers (1)

guidot
guidot

Reputation: 5333

For a function modifying a variable declared on outer scope additionally a declaration of the form

global variable_name

is required in the function (typically directly after function declaration.

Upvotes: 2

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