CODEWITHSUNDEEP
scalatype-inferencehigher-kinded-types
Juh_
Juh_

Reputation: 15529

Compilation issue with type alias of higherKinds

I have a trait like

trait T{
  type F[_]
  def get[A](f: F[A]): A
}

But I cannot implement it

type Id[+A] = A // same as shapeless Id

object O extends T{
  type F[_] = Id[_]
  def get[A](f: F[A]): A = f // 
}
// error: type mismatch;
// found   : f.type (with underlying type O.F[A])
// required: A
//       def get[A](f: F[A]): A = f
//                                ^

(note I think i should work if I cast f.asIntanceOf[A] but I didn't try)

I have the same problem with Future:

import scala.concurrent.Await
import scala.concurrent.Future
import scala.concurrent.duration.Duration
object O2 extends T{
  type F[_] = Future[_]
  def get[A](f: F[A]): A = Awaits.result(f, Duration.Inf)
}
// error: type mismatch;
// found   : scala.concurrent.Future[_$1] where type _$1
// required: scala.concurrent.Awaitable[A]
//   def get[A](f: F[A]): A = Await.result(f, Duration.Inf)
//                                         ^

Can someone explain to me what's happening? Why the compiler cannot understand the actual type F[A] is using the above type alias?

Upvotes: 3

Views: 45

Answers (1)

Andrey Tyukin
Andrey Tyukin

Reputation: 44908

You probably wanted to write

type F[X] = Id[X]

and 

type F[X] = Future[X]

Example:

trait T { type F[_]; def get[A](f: F[A]): A }
object Foo extends T { 
  type F[X] = List[X]
  def get[A](f: List[A]): A = f.head 
}

I assume that you will have to wait for Dotty and full support for type-lambdas until you can drop the redundant argument on both sides.

Upvotes: 4

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