CODEWITHSUNDEEP
djangopdb
Bunny Rabbit
Bunny Rabbit

Reputation: 8411

problem with pdb

on a django shell i tried 

from django import forms
class A(forms.Form):
    x = forms.CharField()
ao = A()
import pdb 
pdb.run('ao.as_table')

but on the last statement , after hitting continue for the first time i am getting a stacktrace as 

/usr/lib/python2.6/pdb.pyc in run(statement, globals, locals)
   1218 
   1219 def run(statement, globals=None, locals=None):
-> 1220     Pdb().run(statement, globals, locals)
   1221 
   1222 def runeval(expression, globals=None, locals=None):

/usr/lib/python2.6/bdb.pyc in run(self, cmd, globals, locals)
    370             cmd = cmd+'\n'
    371         try:
--> 372             exec cmd in globals, locals
    373         except BdbQuit:
    374             pass

/usr/lib/pymodules/python2.6/IPython/FakeModule.pyc in <module>()

NameError: name 'ao' is not defined

what went wrong ? :(

Upvotes: 1

Views: 720

Answers (2)

simplyharsh
simplyharsh

Reputation: 36393

Two things.

  • First, use the statement argument as a call. i.e "ao.as_table()" with () as suffix.
  • Second, pass a keyword argument locals=locals() to the function. You can also pass globals=globals(). Don't use locals() as positional argument, as it will get assigned to globals as run(statement[, globals[, locals]]) takes globals as first argument. So if the first positional argument is locals() it will be mistaken as globals while running your code.

It should be

pdb.run('print ao.as_table()' locals=locals())

Upvotes: 3

Shailesh Kumar
Shailesh Kumar

Reputation: 6977

pdb.run('print ao.as_table()', locals())

Basically pass on the locals() dictionary

Upvotes: 4

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