CODEWITHSUNDEEP
pythonregexpandascontains
neanderslob
neanderslob

Reputation: 2693

Using a variable within a regular expression in Pandas str.contains()

I'm attempting to select rows from a dataframe using the pandas str.contains() function with a regular expression that contains a variable as shown below.

df = pd.DataFrame(["A test Case","Another Testing Case"], columns=list("A"))
variable = "test"
df[df["A"].str.contains(r'\b' + variable + '\b', regex=True, case=False)] #Returns nothing

While the above returns nothing, the following returns the appropriate row as expected

df[df["A"].str.contains(r'\btest\b', regex=True, case=False)] #Returns values as expected

Any help would be appreciated.

Upvotes: 15

Views: 19600

Answers (3)

hamidreza zarrabi
hamidreza zarrabi

Reputation: 146

Following command work for me:
df.query('text.str.contains(@variable)')

Upvotes: 0

Phanish Chava
Phanish Chava

Reputation: 56

I had the exact same problem when parsing a 'variable' to str.contains(variable).

Try using str.contains(variable, regex=False)

It worked for me perfectly.

Upvotes: -1

cs95
cs95

Reputation: 402483

Both word boundary characters must be inside raw strings. Why not use some sort of string formatting instead? String concatenation as a rule is generally discouraged.

df[df["A"].str.contains(fr'\b{variable}\b', regex=True, case=False)] 
# Or, 
# df[df["A"].str.contains(r'\b{}\b'.format(variable), regex=True, case=False)] 

             A
0  A test Case

Upvotes: 23

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