CODEWITHSUNDEEP
rlist
John Doe
John Doe

Reputation: 222

Convenient way of defining a list as observation in a data.frame

Is there a way of defining a list-as-observation inside the loop? For instance, I could just run the following code to replace each list-as-observation whenever another observation of a data.frame meets a certain condition, like in the code below, but I need to create the lists as a set of NULL lists before running the loop. Also, I haven't figured out how to place the list in the line that creates the data.frame -- is there way to do this?

Here it is the code:

#line that creates the data.frame: I wished to know how to place the list 
#(at the line after creating the data.frame object) inside the data.frame function.

df = data.frame(x=1:10)

#line that creates the list as NULL values before replacing them in the loop

df$y = list(c())

#random replacement condition 

df$z = c(0,0,1,0,1,0,1,0,0,0)

#Loop: could I create the list variable on the run without creating it before the loop?

for(i in 1:10) {

  if (df$z[i]==1) {

  df$y[i] = list(c("a","b"))  


  }

}

If there is a more state of the art or a recommend way of doing this following some set of principles (e.g. tidy) I would be glad if someone could refer to it.

Upvotes: 0

Views: 41

Answers (1)

Ronak Shah
Ronak Shah

Reputation: 389165

I am not sure why you want to do this but you can reduce your code to

df <- data.frame(x = 1:10, z = c(0,0,1,0,1,0,1,0,0,0))
df$y <- ifelse(df$z == 1, list(c("a","b")), list())

and it would give the same result.

Upvotes: 1

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