CODEWITHSUNDEEP
bashshellsh
floxcc
floxcc

Reputation: 70

Read after 'while read lines' not evaluated (SHELL)

I am currently trying to debug some scripts I've made and I cannot find a way for a 'read' instruction to be executed.

To summarize, I've got two functions, one with a 'while read lines' that is called after a pipe, and another functions that read user input after while read is processed.

Let me now explain this with code :

echo "$lines" | saveLines

saveLines(){
  # ...
  while read line ; do
    # processing lines
  done
  myOtherFunction
}

myOtherFunction(){
  echo "I am here !" # <= This is printed in console
  read -p "Type in : " tmp  # <= Input is never asked to user, and the message is not printed
  echo "I now am here !" # <= This is printed in console
}

This code is simplified but the spirit is here. I tried to insert a 'read' instruction before the 'read -p ...', it did not seems to change things...

So please, if you can show my error or tell me why this behavior is expected, I would be very happy. Thanks for you time

Upvotes: 0

Views: 165

Answers (1)

ErikMD
ErikMD

Reputation: 14723

This question is very close to that other question, in a slightly different context. To be more precise and as explained by the OP, the command run was

echo "$lines" | saveLines

meaning that the standard input of the code executed by saveLines wasn't the terminal anymore, but the same descriptor as the standard output of the echo... command.

To solve this it thus suffices to replace

…
read -p "Type in : " tmp
…

with

…
read -p "Type in : " tmp </dev/tty
…

Upvotes: 1

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