CODEWITHSUNDEEP
cfgets
user12211554
user12211554

Reputation:

How can I refer to a file as the stream for fgets()?

fgets() returns a string from a provided stream. One is stdin, which is the user input from the terminal. I know how to do this, but if I am using compiled c code in applications, this is not very useful. It would be more useful if I could get a string from a file. That would be cool. Apparently, there is some way to provide a text file as the stream. Suppose I have the following code:

#include <stdio.h>

int main(int argc, const char *argv){
    char *TextFromFile[16];
    fgets(TextFromFile, 16, /*stream that refers to txt file*/);
    printf("%s\n", TextFromFile);
    return 0;
}

Suppose there is a text file in the same directory as the c file. How can I make the printf() function print the contents of the text file?

Upvotes: 0

Views: 856

Answers (2)

user12211554
user12211554

Reputation:

Later I found out the problem. fopen is stupid. Using ./file.txt or others will not work. I need to use the whole file path to do it. 

FILE (*File) = fopen("/home/asadefa/Desktop/txt.txt", "r");
char FData[0x100];
memset(FData, '\0', 0x100);
for(z = 0; z < 0x100; ++z) {
    fgets(FData, 0x100, File);
}
fclose(File);

I should have noted that the full file path is used.

Upvotes: 0

ryyker
ryyker

Reputation: 23218

Given the following is defined;

char *TextFromFile[16]; 

char TextFromFile[16]; //note "*" has been removed 
const char fileSpecToSource[] = {"some path location\\someFileName.txt"};//Windows
const char fileSpecToSource[] = {"some path location/someFileName.txt"};//Linux

From within a function, the statement:

FILE *fp = fopen(fileSpecToSource, "r");//file location is local to source directory.

if successful (i.e. fp != NULL), fp can be used as the stream argument in:

fgets(TextFromFile, 16, fp);

Upvotes: 2

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