Reputation: 181
Hey guys simple question how can I display in the second dropdown information that depends of the first one.
Example. I have this:
var option = document.getElementById("second_dropdown").getElementsByTagName("option");
for (var j = 0; j < option.lenght; j++) {
option[j].disabled = true;
}
<!-- DROPDOWN 1 -->
<select id="first_dropdown" name="first_d">
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
</select>
<!-- DROPDOWN 2 -->
<select id="second_dropdown" name="second_d">
<optgroup label="1">
<option value="100">blabla</option>
<option value="101">blabla</option>
<option value="102">blabla</option>
</option>
<optgroup label="2">
<option value="103">blabla</option>
<option value="104">blabla</option>
<option value="105">blabla</option>
</option>
<optgroup label="3">
<option value="106">blabla</option>
<option value="107">blabla</option>
<option value="108">blabla</option>
</option>
<select>
And I would like to display in dropdown 2 only the optgroup that has been selected in dropdown 1 ...
I really don't know about js so I hope that i explained it well and thanks in advance :)
But here I only disable all (and I want to disable only what's not selected in dropdown one) and I don't want to disable but I want to undisplay.
Upvotes: 0
Views: 52
Reputation: 68923
You can try the following way:
var firstDD = document.getElementById('first_dropdown');
firstDD.addEventListener('change',changeDD);
function changeDD(){
var fValue = firstDD.value;
document.querySelectorAll('#second_dropdown > optgroup').forEach(function(el){
if(el.label != fValue )
el.style.display='none';
else
el.style.display='block';
});
document.querySelector('#second_dropdown').value = "";
}
changeDD(firstDD);
<select id="first_dropdown" name="first_d">
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
</select>
<select id="second_dropdown" name="second_d">
<optgroup label="1">
<option value="100">blabla</option>
<option value="101">blabla</option>
<option value="102">blabla</option>
</optgroup>
<optgroup label="2">
<option value="103">blabla 21</option>
<option value="104">blabla</option>
<option value="105">blabla</option>
</optgroup>
<optgroup label="3">
<option value="106">blabla</option>
<option value="107">blabla</option>
<option value="108">blabla</option>
</optgroup>
<select>
Upvotes: 1
Reputation: 21489
Loop through optgroup
of second <select>
and in loop check if value
of first select is equal to label
of optgroup
remove disabled
of it.
document.querySelector("#first_dropdown").onchange = function(){
var val = this.value;
document.querySelectorAll("#second_dropdown optgroup").forEach(function(ele){
ele.disabled = ele.label != val
});
};
<select id="first_dropdown" name="first_d">
<option value="1">Option 1</option>
<option value="2">Option 2</option>
<option value="3">Option 3</option>
</select>
<select id="second_dropdown" name="second_d">
<optgroup label="1">
<option value="100">blabla</option>
<option value="101">blabla</option>
<option value="102">blabla</option>
</optgroup>
<optgroup label="2">
<option value="103">blabla</option>
<option value="104">blabla</option>
<option value="105">blabla</option>
</optgroup>
<optgroup label="3">
<option value="106">blabla</option>
<option value="107">blabla</option>
<option value="108">blabla</option>
</optgroup>
<select>
Also you should change display
property of element if you want to show/hide optgroup
document.querySelector("#first_dropdown").onchange = function(){
var val = this.value;
document.querySelectorAll("#second_dropdown optgroup").forEach(function(ele){
ele.style.display = ele.label==val ? "block" : "none";
});
};
Also you can do this work simplify using jquery
$("#first_dropdown").change(function(e){
$("#second_dropdown optgroup").css("display", function(){
return this.label==e.target.value ? "block" : "none";
});
});
Upvotes: 1