CODEWITHSUNDEEP
pythonrenamefilenamesspaces
Michael
Michael

Reputation: 3

(Python) Delete consecutive spaces in filename; leave a single space

1.st step: underscore to space

path = os.getcwd()
filenames = os.listdir(path)
for filename in filenames:
os.rename(os.path.join(path,filename),os.path.join(path, filename.replace("_", " ")))

OUTCOME:

(cant post picture yet.. so:)

WKN_855681(INTEL_CORP._______DL-001)_vom_03.12.2018482523.pdf

Geändert auf: (changed to)

WKN 855681(INTEL CORP.       DL-001) vom 03.12.2018482523.pdf

!This is fine :D

now i like to delete the surplus spaces in the (changed to) state.

PS: im a bloody rookie so please dont kill me yet.

ty

Outcome, I think the text here doesn't show the spaces..? outcome, i think the text here doesnt show the spaces..?

SOLVED STATE: enter image description here

Upvotes: 0

Views: 289

Answers (3)

mad_
mad_

Reputation: 8273

Use regex to replace the surplus spaces to just one

import re
re.sub('\s{1,}',' ',file)

Test

a='WKN 855681(INTEL CORP.       DL-001) vom 03.12.2018482523.pdf'

output

'WKN 855681(INTEL CORP. DL-001) vom 03.12.2018482523.pdf'

Or in a single step replace surplus _ with just one space

re.sub('\_{1,}',' ',file)

Test

a='WKN_855681(INTEL_CORP._______DL-001)_vom_03.12.2018482523.pdf'
re.sub('\_{1,}',' ',a)

Output

'WKN 855681(INTEL CORP. DL-001) vom 03.12.2018482523.pdf'

Upvotes: 1

Daniel
Daniel

Reputation: 42758

Use regular expression:

import re
os.rename(os.path.join(path, filename), os.path.join(path, re.sub('[\s_]+', ' ', filename))

Upvotes: 1

Pedro Lobito
Pedro Lobito

Reputation: 98921

My 2c using glob, re.sub and os.rename: 

import glob, os, re
for fn in glob.glob('C:\\somedir\\*'):
    new_fn = re.sub(" ", "_")
    os.rename(fn, new_fn)

Upvotes: 0

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