CODEWITHSUNDEEP
xslt
user667850
user667850

Reputation: 23

Selecting the first and second node in XSLT

Given the following structure, how to copy the first and the second nodes with all their elements from the document based on the predicate in XSLT:

<list>
  <slot>xx</slot>
   <data>
       <name>xxx</name>
       <age>xxx</age>  
   </data>      
   <data>
       <name>xxx</name>
       <age>xxx</age>  
   </data> 
   <data>
       <name>xxx</name>
       <age>xxx</age>  
   </data> 
</list> 
<list>
  <slot>xx</slot>
   <data>
       <name>xxx</name>
       <age>xxx</age>  
   </data> 
   <data>
       <name>xxx</name>
       <age>xxx</age>  
   </data> 
   <data>
       <name>xxx</name>
       <age>xxx</age>  
   </data> 
</list>

How to select the first and the second occurence of data (without the data element itself, only name, age) from the list, where the slot is equal to a different variable, i.e the first list has the slot=02, but I need the data from the second list, where the slot=01. But it does not really matter the order of the list by a slot as long as slot=$slotvariable.

I tried the following statement, but it did not produce any results:

<xsl:element name="{'Lastdata'}">
  <xsl:copy-of select="list/data[position()=1 and slot = $slotvariable]" />
</xsl:element>
<xsl:element name="{'prevdata'}">
  <xsl:copy-of select="list/data[position()=2 and slot = $slotvariable]" />
</xsl:element>

Any working suggestions would be appreciated

Upvotes: 0

Views: 16474

Answers (2)

Wayne
Wayne

Reputation: 60414

The following stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:variable name="slot" select="'slot1'"/>
    <xsl:template match="/lists/list">
        <xsl:copy-of select="data[../slot=$slot][position()&lt;3]/*"/>
    </xsl:template>
</xsl:stylesheet>

Applied to this source:

<lists>
    <list>
      <slot>slot1</slot>
       <data>
           <name>George</name>
           <age>7</age>  
       </data> 
       <data>
           <name>Bob</name>
           <age>22</age>  
       </data> 
       <data>
           <name>James</name>
           <age>77</age>  
       </data> 
    </list> 
    <list>
      <slot>slot2</slot>
       <data>
           <name>Wendy</name>
           <age>25</age>  
       </data> 
    </list> 
</lists>

Produces the following result:

<name>George</name>
<age>7</age>
<name>Bob</name>
<age>22</age>

Upvotes: 0

Tomalak
Tomalak

Reputation: 338208

If I understood your question correctly, then:

<Lastdata>
  <xsl:copy-of select="list[slot=$slotvariable]/data[1]/*" />
</Lastdata>
<prevdata>
  <xsl:copy-of select="list[slot=$slotvariable]/data[2]/*" />
<prevdata>

Hints:

  • Don't use <xsl:element> unless you have a dynamic name based on an expression.
  • [1] is a shorthand for [position() = 1]

Upvotes: 5

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