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pythonstringpython-3.xdictionarystring-formatting
Giovanni Rescia
Giovanni Rescia

Reputation: 590

Python 3.6+ formatting strings from unpacking dictionaries with missing keys

In Python3.4 you could do the following thing:

class MyDict(dict):
    def __missing__(self, key):
        return "{%s}" % key

And then something like:

d = MyDict()
d['first_name'] = 'Richard'
print('I am {first_name} {last_name}'.format(**d))

Printing, as expected:

I am Richard {last_name}

But this snippet won't work in Python3.6+, returning a KeyError while trying to get the last_name value from the dictionary, is there any workaround for that string formatting to work in the same way as in Python3.4?

Thanks!

Upvotes: 2

Views: 722

Answers (2)

Giovanni Rescia
Giovanni Rescia

Reputation: 590

I solved it using format_map instead of format, following my example:

print('I am {first_name} {last_name}'.format_map(d))

Printed

I am Richard {last_name}

As expected.

Upvotes: 3

jpp
jpp

Reputation: 164613

With Python 3.6+, you can use formatted string literals (PEP 498):

class MyDict(dict):
    def __missing__(self, key):
        return f'{{{key}}}'

d = MyDict()
d['first_name'] = 'Richard'

print(f"I am {d['first_name']} {d['last_name']}")

# I am Richard {last_name}

Upvotes: 1

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