Reputation: 791
I have an array of objects:
objArray = [
{x: 1, y: 7},
{x: 2, y: 14},
{x: 1, z: 9},
{x: 2, z: 18}
{x: 1, n: 6}
{x: 2, n: 16}
]
Is there an efficient way to merge for "X" without a for loop? so that I end up with:
objArray = [
{x: 1, y: 7, z: 9, n: 6},
{x: 2, y: 14, z: 18, n: 16}
]
So look for common objArray[n]["x"]
and merge all hits into one object? It's OK to modify the original array or create a new one.
I'm aware this can be done with a loop, but I'm trying to avoid too many loops for this implementation, though I'm not sure if a reduce or a filter would work for this.
Upvotes: 1
Views: 80
Reputation: 386578
You could take a Map
and group by property x
.
var array = [{ x: 1, y: 7 }, { x: 2, y: 14 }, { x: 1, z: 9 }, { x: 2, z: 18 }, { x: 1, n: 6 }, { x: 2, n: 16 }],
result = Array.from(
array
.reduce((m, o) => m.set(o.x, Object.assign({}, m.get(o.x), o)), new Map)
.values()
);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Upvotes: 3
Reputation: 141829
You can do it with Array#reduce:
const objArray = [
{x: 1, y: 7},
{x: 2, y: 14},
{x: 1, z: 9},
{x: 2, z: 18},
{x: 1, n: 6},
{x: 2, n: 16},
]
const result = Object.values( objArray.reduce(
(p,c) => (p[c.x] = Object.assign( {}, p[c.x], c ), p ), {}
) );
console.log( result );
Upvotes: 3
Reputation: 122047
You could use reduce
method to build an object and then Object.values
to get an array.
const data = [{"x":1,"y":7},{"x":2,"y":14},{"x":1,"z":9},{"x":2,"z":18},{"x":1,"n":6},{"x":2,"n":16}]
const res = data.reduce((r, {x, ...rest}) => {
if(!r[x]) r[x] = {x, ...rest}
else Object.assign(r[x], rest);
return r;
}, {})
const result = Object.values(res);
console.log(result)
Upvotes: 3