How to extract and compare data from a given list of tuples?

Question

CODE:

import datetime


data = [('09', '55', None, 'AC is on', None), ('10', '00',None, 'AC is on', None),('10', '13','fan is on', 'AC is on', 'light is on')]


def calc(data):

    print(data)               #prints the whole table
    while True:
        h=datetime.datetime.today().strftime("%H")              
        mi=datetime.datetime.today().strftime("%M")
        # z=[(i[2],i[3],i[4]) for i in data if i[0] == h and i[1]==mi]
        for i in data: 
            if i[0] == h and i[1]==mi:
                print (i[2],i[3],i[4])
                # sleep(60)
                break

if __name__ == '__main__':
    calc(data)

The first 2 elements inside 'data' are hour and minutes entered by user. The code should take user entered values , that is, data here. and should check with current time and should print i[2],i[3],i[4] as shown in code.

1)I just want the values to be printed once. But, it keeps on checking and prints value for 1 whole minute. The break statement isn't working.

2)Also, is it possible to somehow check and not to print the none?

Answer 1

If I understood correctly you want your program to run until it finds a match between the current time, and the time specified in one of the tuples (i) in data : (data[i][0], data[i][1]), and then print the rest of the tuple : i[2:5]

1. The break is in the for loop scope, not your while loop. You exit the for loop, yes, not your infinite while True loop.
2. I would rather do while match_not_found:, then set match_not_found = True, and have a line match_not_found = False before your break statement.
3. You can use list slicing if you're going to use all remaining items of the tuple.
4. I added an extra if to exclude None of the printed items

Like that :

import datetime


data = [('09', '55', None, 'AC is on', None), ('10', '00',None, 'AC is on', None),('10', '13','fan is on', 'AC is on', 'light is on')]


def calc(data):

    print(data)               #prints the whole table
    match_not_found = True

    while match_not_found:
        h=datetime.datetime.today().strftime("%H")              
        mi=datetime.datetime.today().strftime("%M")
        # z=[(i[2],i[3],i[4]) for i in data if i[0] == h and i[1]==mi]
        for i in data: 
            if i[0] == h and i[1]==mi:
                print ([j for j in i[2:5] if j != None])
                match_not_found = False
                break

if __name__ == '__main__':
    calc(data)

Answer 2

I have done few changes in code.

I dont know why you are using While= True . Because of which it is NOT coming out of loop . So i have removed it

Just added else statement to for check , you can remove it

import datetime


data = [('09', '55', None, 'AC is on', None), ('10', '00',None, 'AC is on', None),('10', '13','fan is on', 'AC is on', 'light is on')]


    def calc(data):

        print(data)               #prints the whole table
        # while True:
        h=datetime.datetime.today().strftime("%H")
        print(h)              
        mi=datetime.datetime.today().strftime("%M")
        print(mi)
        # z=[(i[2],i[3],i[4]) for i in data if i[0] == h and i[1]==mi]
        for i in data: 
            if i[0] == h and i[1]==mi:
                print (i[2],i[3],i[4])
            else:
                print ("It does NOT match")
                # sleep(60)
            break

    if __name__ == '__main__':
         calc(data)

EDITED (works now):

import datetime


data = [('09', '55', None, 'AC is on', None), ('10', '00',None, 'AC is on', None),('10', '52','fan is on', 'AC is on', None)]


def calc(data):

    print(data)               #prints the whole table
    while True:
        h=datetime.datetime.today().strftime("%H")              
        mi=datetime.datetime.today().strftime("%M")
        # z=[(i[2],i[3],i[4]) for i in data if i[0] == h and i[1]==mi]
        for i in data: 
            if i[0] == h and i[1]==mi:
                print (i[2],i[3],i[4])
                # sleep(60)
                exit()

if __name__ == '__main__':
    calc(data)