CODEWITHSUNDEEP
phpstringvariables
Matt McDonald
Matt McDonald

Reputation: 5050

Mixing a PHP variable with a string literal

Say I have a variable $test and it's defined as: $test = 'cheese'

I want to output cheesey, which I can do like this:

echo $test . 'y'

But I would prefer to simplify the code to something more like this (which wouldn't work):

echo "$testy"

Is there a way to have the y be treated as though it were separate from the variable?

Upvotes: 184

Views: 259513

Answers (5)

legolas108
legolas108

Reputation: 239

"${test}y" is deprecated since PHP 8.2, use "{$test}y" instead. (Note the $ being covered by the curly braces.)

Upvotes: 5

Rizwan
Rizwan

Reputation: 89

Example:

$test = "chees";
"${test}y";

It will output:

cheesy

It is exactly what you are looking for.

Upvotes: 8

Pascal MARTIN
Pascal MARTIN

Reputation: 401022

You can use {} arround your variable, to separate it from what's after:

echo "{$test}y"

As reference, you can take a look to the Variable parsing - Complex (curly) syntax section of the PHP manual.

Upvotes: 62

earlyburg
earlyburg

Reputation: 11

$bucket = '$node->' . $fieldname . "['und'][0]['value'] = " . '$form_state' . "['values']['" . $fieldname . "']";

print $bucket;

yields:

$node->mindd_2_study_status['und'][0]['value'] = $form_state['values']
['mindd_2_study_status']

Upvotes: -2

alex
alex

Reputation: 490273

echo "{$test}y";

You can use braces to remove ambiguity when interpolating variables directly in strings.

Also, this doesn't work with single quotes. So:

echo '{$test}y';

will output 

{$test}y

Upvotes: 318

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