CODEWITHSUNDEEP
python-3.xreplace
Bruce
Bruce

Reputation: 81

Python 3 remove chars from Tuples

My results look like this:

('04', 3)
('06', 1) 
('07', 1) 
('09', 2)

I want them to look like this:

04 3
06 1
07 1
09 2

I've tried split (Not a string, can't do that) .replace (requires string as left operand not a tuple.) I 'think' I've tried list comprehension correctly. I'm not clear what I should actually be doing to accomplish my desired end result. I'm trying to use n00b functions since I'm learning this therefore, I'm ignore Lambda as I have no clue what that is. I am trying to stick to list, dictionary, comprehension, slice etc at this point.

My example below won't run as written, I'm just trying to show my last attempt. When I comment out lines 15, 16, 17, it runs and creates the example shown above.

fname = input("Enter file:")
if len(fname) < 1 : fname = "mbox-short.txt"
emails = open(fname)
counts=dict()
for email in emails:
    result=email.startswith('From ')
    if result is True:
        time=(email.split()[5])
        hour=(time.split(':')[0])
        counts[hour]=counts.get(hour, 0) +1
tmp=list()
for k, v in counts.items():
    tmp.append( (k, v) )
    tmp.sort()
    for char in tmp:
        if char in "(',)":
            tmp.replace(char,'')
for k in tmp:
    print (k)

Upvotes: 0

Views: 46

Answers (4)

ozcanyarimdunya
ozcanyarimdunya

Reputation: 2544

This may help you 

# ....
# Rest of your code
# ....
tmp=list()
for k, v in counts.items():
    tmp.append( (int(k), int(v)) ) # !!! make it integer
    tmp.sort()

for k in tmp:
    print (k)

Upvotes: 1

Austin
Austin

Reputation: 26039

Assuming [('04', 3), ('06', 1), ('07', 1), ('09', 2)] is your input, you could just do:

tupls = [('04', 3), ('06', 1), ('07', 1), ('09', 2)]

for x, y in tupls:
    print(x, y)

# 04 3
# 06 1
# 07 1
# 09 2

Upvotes: 1

Patrick Artner
Patrick Artner

Reputation: 51683

mydata = [('04', 3), ('06', 1), ('07', 1), ('09', 2)]

for tup in mydata:
    print(*tup)    # this uses the default sep = " " for print
                   # *tup provides each element of tup to print

Output:

04 3
06 1
07 1
09 2

See

Upvotes: 1

blhsing
blhsing

Reputation: 106901

You can use the str.join method on a space:

for k in tmp:
    print (' '.join(k))

Upvotes: 1

Related Questions