Reputation: 6152
can someone point me to how I can write this in syntax-parse/case?
[(list e ...) #`(list #,(f #'e) ...)]
basically I'd like each element in the list to be processed individually by f
in unsyntax. I don't think the above is the right syntax?
Upvotes: 0
Views: 70
Reputation: 22102
You can use unsyntax-splicing
(which can be abbreviated as #,@
) to embed result of list returning expression as individual elements of outer list. Then you can use map
procedure to apply f
over all elements of list returned by (syntax->list #'(e ...))
expression. In the end it will look like this:
#`(list #,@(map f (syntax->list #'(e ...))))
Upvotes: 1