Reputation: 55
I'm going to make a query to get data with index of subarray which number is even number.
Input value:
{
"_id" : ObjectId("5b3b206c4a25da19d05f41a2"),
"numbers" : [
{
"name" : "Foobar",
"lines" : [
{
"number" : 6,
},
{
"number" : 11,
},
{
"number" : 15,
},
{
"number" : 8,
}
]
}
]
}
Desired output:
{
"_id" : ObjectId("5b3b206c4a25da19d05f41a2"),
"numbers" : [
{
"name" : "Foobar",
"lines" : [
{
"index" : 0,
"number" : 6,
},
{
"index" : 3,
"number" : 8,
}
]
}
]
}
The most important is to get the index of items of "lines".
Upvotes: 2
Views: 1432
Reputation: 46461
You need to use $map
to iterate over the first array and then $filter
with the nested array.
db.collection.aggregate([
{ "$project": {
"numbers": {
"$map": {
"input": "$numbers",
"as": "nn",
"in": {
"name": "$$nn.name",
"lines": {
"$filter": {
"input": {
"$map": {
"input": "$$nn.lines",
"as": "ll",
"in": {
"number": "$$ll.number",
"index": { "$indexOfArray": ["$$nn.lines.number", "$$ll.number"] }
}
}
},
"as": "ll",
"cond": { "$eq": [{ "$mod": ["$$ll.number", 2] }, 0] }
}
}
}
}
}
}}
])
Even if you need some more aggregation trick
db.collection.aggregate([
{ "$project": {
"numbers": {
"$map": {
"input": {
"$map": {
"input": "$numbers",
"as": "nn",
"in": {
"name": "$$nn.name",
"lines": {
"$filter": {
"input": { "$zip": { "inputs": ["$$nn.lines", { "$range": [0, { "$size": "$$nn.lines" }] }] }},
"as": "ll",
"cond": {
"$let": {
"vars": { "num": { "$arrayElemAt": ["$$ll", 0] }},
"in": { "$eq": [{ "$mod": ["$$num.number", 2] }, 0] }
}
}
}
}
}
}
},
"as": "nn",
"in": {
"name": "$$nn.name",
"lines": {
"$map": {
"input": "$$nn.lines",
"as": "kk",
"in": {
"number": { "$arrayElemAt": ["$$kk.number", 0] },
"index": { "$arrayElemAt": ["$$kk", 1] }
}
}
}
}
}
}
}}
])
Finally both will give you similar Output
[
{
"_id": ObjectId("5b3b206c4a25da19d05f41a2"),
"numbers": [
{
"name": "Foobar",
"lines": [
{
"index": 0,
"number": 6
},
{
"index": 3,
"number": 8
}
]
}
]
}
]
Upvotes: 3