Reputation: 29
I have data in the below format
id idnew
1 2
3 4
2
4 7
6 8
7
Result Should be something like this
ID should be followed by idnew
1
2
3
4
2
4
7
6
8
7
Thanks in advance
Upvotes: 0
Views: 177
Reputation: 2516
Using Cross Apply
;WITH CTE (id,idnew)
AS
(
SELECT 1,2 UNION ALL
SELECT 3,4 UNION ALL
SELECT 2,NULL UNION ALL
SELECT 4,7 UNION ALL
SELECT 6,8 UNION ALL
SELECT 7,NULL
)
SELECT New
FROM CTE
CROSS APPLY ( VALUES (id),(idnew))AS Dt (New)
WHERE dt.New IS NOT NULL
Result
New
---
1
2
3
4
2
4
7
6
8
7
Upvotes: 0
Reputation: 90
This should maintain the order:
SELECT id
FROM (
SELECT id, ROW_NUMBER() OVER (ORDER BY id) AS RowNumber
FROM myTable
UNION ALL
SELECT idnew, ROW_NUMBER() OVER (ORDER BY idnew) +
(SELECT COUNT(*) FROM dbo.myTable) AS RowNumber
FROM myTable
WHERE idnew IS NOT NULL
) a
ORDER BY RowNumber
I am assuming the id column is NOT NULL-able.
NOTE: If you want to keep the NULL values from the idnew column AND maintain the order, then remove the WHERE clause and ORDER BY id in the second select:
SELECT id
FROM (
SELECT id, ROW_NUMBER() OVER (ORDER BY id) AS RowNumber
FROM myTable
UNION ALL
SELECT idnew, ROW_NUMBER() OVER (ORDER BY id) +
(SELECT COUNT(*) FROM dbo.myTable) AS RowNumber
FROM myTable
) a
ORDER BY RowNumber
Upvotes: 2
Reputation: 1248
This is fully tested, try it here: https://rextester.com/DVZXO21058
Setting up the table as you described:
CREATE TABLE myTable (id INT, idnew INT);
INSERT INTO myTable (id, idnew)
VALUES (1, 2),
(3, 4),
(2, NULL),
(4, 7),
(6, 8),
(7, NULL);
SELECT * FROM myTable;
Here is the query to do the trick:
SELECT mixed_id FROM
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS row_num,
id,
idnew
FROM myTable
) AS x
UNPIVOT
(
mixed_id for item in (id, idnew)
) AS y
WHERE mixed_id IS NOT NULL
ORDER BY row_num, mixed_id;
In order not to further complicate the query, this is taking advantage of 'id' would rank ahead of 'idnew' as a string. I believe string ranking is not the key issue here.
Upvotes: 1