CODEWITHSUNDEEP
pythonpython-3.x
user_not_define
user_not_define

Reputation: 33

How to get all pair of items from the list without using the itertools import combination

I have a list and I want all possible combinations of items of a list.

from itertools import combinations
l = [1,2,3]
for i in combinations(l,2):
    print(i) // (1, 2) (1,3) (2,3)

I want the same output but without using the itertools. I tried:

l = [1,2,3]
for i in l:
    for j in l:
        print((i,j)) // (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)

How can I get the same output without using itertools?

Upvotes: 0

Views: 244

Answers (3)

user10775237
user10775237

Reputation:

You can do this in a one liner just for efficiency: 

l = [1, 2, 3]

([print(i, j) for i in l for j in l])

Upvotes: 0

vishes_shell
vishes_shell

Reputation: 23484

You can find sample implementation of itertools.combinations in docs:

Roughly equivalent to:

def combinations(iterable, r):
    # combinations('ABCD', 2) --> AB AC AD BC BD CD
    # combinations(range(4), 3) --> 012 013 023 123
    pool = tuple(iterable)
    n = len(pool)
    if r > n:
        return
    indices = list(range(r))
    yield tuple(pool[i] for i in indices)
    while True:
        for i in reversed(range(r)):
            if indices[i] != i + n - r:
                break
        else:
            return
        indices[i] += 1
        for j in range(i+1, r):
            indices[j] = indices[j-1] + 1
        yield tuple(pool[i] for i in indices)

Upvotes: 1

Vinay Bharadhwaj
Vinay Bharadhwaj

Reputation: 163

Maybe try this

l = [1, 2, 3]
for i in l:
    for j in l:
        if(j <= i):
            continue
        else:
            print(i, j)

Upvotes: 1

Related Questions