Reputation: 49
I have 3 radio buttons and I would like to hide one of them. All 3 radio buttons have the same class but different values. I wrote code like this below but it's not working because the element is hidden on every radio button. Can you help me with this? Here is my code:
$(document).ready(function() {
if ($('input.delivery_option_radio').val('49,').is(":checked")) {
$(".hide").css("display", "none");
alert("test");
}
});
Upvotes: 1
Views: 165
Reputation: 24
if your sure that value in radio buttons is "49," not (49)
try this:
$('.hide[value="49,"]').hide();
else
$('.hide[value="49"]').hide();
Upvotes: 0
Reputation: 21489
Your code is wrong because you trying to set value of input to 49,
and hide all .hide
elements.
You don't need to if
, just use Attribute Equals [name=”value”]
and :checked
selectors to do this work.
$(".delivery_option_radio[value='49']:checked").hide();
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<input type="radio" class="delivery_option_radio" value="48">
<input type="radio" class="delivery_option_radio" value="49" checked>
<input type="radio" class="delivery_option_radio" value="50">
Upvotes: 0
Reputation: 44087
You're setting the value, not selecting. Try this in your if statement instead:
if($("input.delivery_radio_option[value=49]").is(":checked")) {...}
Upvotes: 1